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Q: What is the molarity of a solution made by dissolving 6 moles of NaOH in 3kg of water?

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The molarity is 0,33.

The molarity is 0,2.

since molarity = (number of moles) / (volume of solution), the molarity of a solution with 2.3 moles of sodium chloride in 0.45 liters of water will be 5.11 moles.

The molarity is 2 (or 80 g/L).

what is the molarity of a solution prepared by dissolving 36.0g of NaOH in enough water to make 1.50 liter of solution?

1.99 M

Molarity (M) represents the moles of a solute per liter of a solvent. In this case, sucrose is the solute and water is the solvent. First, convert your 125g of sucrose to moles...molar mass of sucrose = 342.34 soo you have .365 moles of sucrose. Since you have exactly one L of solution, the molarity of the solution is .365 M Molarity (M) represents the moles of a solute per liter of a solvent. In this case, sucrose is the solute and water is the solvent. First, convert your 125g of sucrose to moles...molar mass of sucrose = 342.34 soo you have .365 moles of sucrose. Since you have exactly one L of solution, the molarity of the solution is .365 M

Find moles of HCl first. 1.56 grams HCl (1mole HCl/36.458 grams) = 0.0428 moles HCl Molarity = moles of solute/volume of solution Molarity = 0.0428 moles/26.8 ml = 0.00160 milli-Molarity, or more to the point; = 1.60 X 10^-6 Molarity of HCl

Molarity= Number of moles of solute/Liters of solution 50 grams KOH 700 ML to .7 Liters of h2o Molar Mass of KOH= 56 50 divided by 56 = .89 moles Molarity= .89 mol/.7 L = 1.27 MOLARITY

Get moles NaCl and change 245 ml to 0.245 Liters. 3.8 grams NaCl (1 mole NaCl/58.54 grams) = 0.0650 moles NaCl Molarity = moles of solute/Liters of solution Molarity = 0.0650 moles NaCl/0.245 Liters = 0.27 M NaCl ----------------------

The molarity of KNO3 is 0,058.

.62 M is the molarity of the solution made by dissolving 22.4 g of LiClO4 3H2O in 225 mL of water.

Molarity = moles of solute/Liters of solution Molarity = 10 moles salt/20 Liters solution = 0.50 M salt solution ----------------------------

The molarity of a solution made by dissolving 23,4 g of sodium sulphate in enough water to make up a 125 mL solution is 1,318.

Molarity = moles solute/liter solutionmoles solute = 7 g NaCl x 1 mol NaCl/58 g NaCl = 0.12 moles NaClliters of solution = 450.0 ml x 1 L/1000 ml = 0.450 litersmolarity = 0.12 moles/0.450 liters = 0.268 M = 0.3 M (one sig fig)

Molarity = moles of solute/Liters of solution Molarity = 6 Moles NaCl/2 Liters = 3 M NaCl ========

The molarity is 6 mol/l.

molarity = moles/litre [solution] = 12 mol/6 L [solution] = 2 mol/L = 2 M

6 kg = 6000 grams and density of water = 1.00 grams/milliliters. 1.00 g/ml = 6000 grams/X ml = 6000 ml which = 6 liters ======================== Molarity = moles of solute/Liters of solution Molarity = 2 moles NaOH/6 Liters = 0.3 M NaOH solution -----------------------------

The molarity is figured out by the number of moles of NaOH over the number of liters of water. so if the molarity is 0.5M and there is 1.0L of water then there has to be 0.5 moles of NaOH in the solution.

1620 ml = 1.62 Liters Molarity = moles of solute/Liters of solution Molarity = 2 moles NaOH/1.62 Liters = 1 M NaOH solution ===============

Molarity = moles of solute/Liters of solution 10 grams of compound ( 1mol/100g ) = 0.1 mole Molarity = 0.1 mol/1 Liter = 0.1

Molarity = number of moles / number of liters. For this question the number of moles is 3 and the number of liters is 0.5 So 3/0.5 = 6 The solution is 6 M.

3 moles in 1 liter = 3 M

By dissolving the same number of moles of each substance in the same volume of water