Mamoraka Mamaregane
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This ratio is 1:2.
The number of moles is 0,0038.
The number of moles is 1,8.
First construct a a balanced equation for the reaction : 2Na + 2H2O --> 2NaOH + H2 From the equation, we know that the ratio of Sodium(Na) to the ratio of Sodium Hydroxide(NaOH) is the same. Ar of Na = 23g/mol Number of moles = mass / Ar = 46g / 23g/mol = 2mol (moles of Na used) Since ratio of Na to NaOH is the same, therefore there are also 2 moles of NaOH formed.
The same number of moles for each.
Determine the number of moles 15.5 g NaOH 15.5 g NaOH x (1 mole NaOH/39.9971 grams NaOH) = 0.388 moles NaOH Molarity = moles NaOH/L solution 0.540 M = 0.388 moles NaOH/L soln L soln = 0.718 L --> A
Molarity = moles of solute/Liters of solution 3.42 M NaOH = 1.3 moles NaOH/Liters NaOH Liters NaOH = 1.3 moles NaOH/3.42 M NaOH = 0.38 Liters
3.42 moles NaOH (39.998 grams/1 mole NaOH) = 137 grams NaOH
Need moles sodium hydroxide first.80 grams NaOH (1 mole NaOH/39.998 grams) = 2.000 moles NaOHMolarity = moles of solute/Liters of solutionMolality = 2.000 moles NaOH/1 liter= 2 M NaOH solution===============
1st Get the balanced equation NaOH + HCl -> NaCl + H2O Find the number of moles in HCl; n = cv n = 0.46x0.61 n = 0.2806 moles the number of moles of HCl and NaOH is the same so 0.2806moles will be needed
moles = mass/Mr moles = 100/(23+16+1) moles of NaOH = 2.5mol
8 grams NaOH (1 mole NaOH/39.998 grams) = 0.2 moles NaOH