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How many moles are in 95.0 gram of octane?
how many moles are in 95.0 gram of octane?
How many moles of are present in 16.0 of octane?
C8H18. I assume you mean how many moles octane in 16 grams. 16 grams C8H18 (1 mole C8H18/114.224 grams) = 0.140 moles octane
How many moles of H2O are produced when 0.721mol of octane is burned?
6,49 moles of water are obtained.
What is the Delta H value for liquid octane?
10,800 kJ (per 2 moles of octane; the balanced chemical equation)
How many moles of water will be produced from 1 mole of octane?
9
How many moles of carbon dioxide are formed in the complete combustion of one mole of octane C8H18?
The answer is 8 moles CO2.
How many moles of H2O are produced when 0.468 mol of octane is burned?
It forms H2O when burned.There are 3.744 moles of H2O after burned.
How many moles of carbon and hydrogen are there in 5 moles of octane?
Balanced equation. 2C8H18 + 25O2 -> 16CO2 + 18H2O 5.5 moles C8H18 (25 moles O2/2 moles C8H18) = 68.75 moles O2 needed
How many moles of water can be produced by burning 325g of octane in excess oxygen?
Balanced equation: 2C8H18 + 25O2 ==> 16CO2 + 18H2Omoles of octane used: 325 g x 1 mole/114g = 2.85 moles octanemoles H2O produced: 18 moles H2O/2 moles C8H18 x 2.85 moles C8H18 = 25.65 moles H2O
How much co2 is formed from the burning of 1.8 kg of octane?
The formula for normal octane is C8H10. Each mole burned creates 8 moles of CO2. A mole of octane is 106 grams, 8 moles of CO2 is 8x44 = 352 grams So 1.8 kg of octane would produce 1.8x(352/106) = 5.98 g CO2. As the octane value is given to 1 decimal place the answer can be no more accurate so 6.0 kg.
How many moles of water are in this reaction 2C8H18 25O2- 16CO2 18H2O?
the reaction is from the combustion of Octane
What weight of water is produced burning 19.8grams of octane?
The formula for normal octane is C8H18. Its molar mass is 114.23 g mol−1 The formula for its combustion is 2C8H18 + 25O2 --> 16CO2 + 18H2O So 1 mole of octane gives 9 moles of water. One mole of water has a mass of 18 g 19.8 g of octane is 114.23/19.8 moles so its combustions gives ((114.23/19.8) x 9 x 18 ) = 934.61 g of water
