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What double displacement reaction is PbI2 2NaNO3?
In the English language this reaction is called counter-ion exchange double displacement reaction.
What is an insoluble compound formed in a double displacement reaction?
An example of an insoluble compound formed in a double displacement reaction is a precipitate, such as silver chloride (AgCl) or lead iodide (PbI2). When two soluble ionic compounds react in a double displacement reaction, they may form an insoluble product that precipitates out of solution.
Potassium iodide plus lead nitrate?
When potassium iodide is mixed with lead nitrate, a double displacement reaction occurs. The products formed are lead iodide and potassium nitrate. Lead iodide is a yellow precipitate that forms during the reaction.
What is the chemical reaction type when lead II nitrate is mixed with potassium iodide?
Potassium iodide and lead nitrate produces golden yellow precipitate of lead iodide and potassium nitrate. This reaction is a double displacement reaction and also it can be called a precipitation reaction as lead iodide gets precipitated. 2KI+Pb(NO3)2-->PbI2 + 2KNO3
When an aqueous solution of lead(II) nitrate is mixed with an aqueous solution of sodium iodide an aqueous solution of sodium nitrate and a yellow solid lead iodide are formed.?
Lead(II) nitrate and sodium iodide undergo a double displacement reaction to form sodium nitrate and lead(II) iodide, which is a slightly soluble yellow solid. The balanced chemical equation for this reaction is: Pb(NO3)2(aq) + 2NaI(aq) -> 2NaNO3(aq) + PbI2(s)
What is the balanced equation when Pb(NO3)2 NaL reacts with PbL2 NaNO3?
The balanced equation for the reaction between lead(II) nitrate (Pb(NO3)2) and sodium iodide (NaI) to form lead(II) iodide (PbI2) and sodium nitrate (NaNO3) is: Pb(NO3)2 + 2NaI -> PbI2 + 2NaNO3
Balance Equation.When an aqueous solution of lead II nitrate is mixed with an aqueous solution of sodium iodide an aqueous solution of sodium nitrate and a yellow solid lead iodide are formed?
Pb(NO3)2(aq)+2NaI(aq)=2NaNO3(aq)+PbI2(s)
Equation for lead nitrate and calcium iodide are combined?
When lead nitrate and calcium iodide are combined, the following double displacement reaction occurs: Pb(NO3)2 + CaI2 → 2PbI2 + Ca(NO3)2. Lead iodide (PbI2) and calcium nitrate (Ca(NO3)2) are formed as the products.
What type of reaction is pb (no3)2 plus 2ki?
The reaction between lead(II) nitrate (Pb(NO3)2) and potassium iodide (KI) is a double displacement reaction. The lead cation (Pb2+) swaps its nitrate anions (NO3-) with the potassium cation (K+) in the reactants, forming lead(II) iodide (PbI2) and potassium nitrate (KNO3).
What react to lead II nitrate and sodium iodide to make lead iodide and sodium nitrate?
When reactants lead(II) nitrate and sodium iodide are combined, a double displacement reaction occurs. Lead(II) iodide (insoluble in water) and sodium nitrate are formed, leading to a white precipitate of lead(II) iodide and a solution of sodium nitrate.
Is Pb(NO3)2 2KI PbI2 2KNO3 neutralisation or precipitation?
Pb(NO3)2 + 2KI ==> PbI2 + 2KNO3 is a precipitation reaction. The PbI2 is insoluble in water and will precipitate. It is NOT neutralization, because you do not have an acid reacting with a base.
Stoichiometry problems. LeadII nitrate and sodium iodide react to be double replacement If 187.0g of sodium iodide are used calculate the mass of each product formed?
First, balance the chemical equation to be Pb(NO3)2 + 2NaI -> PbI2 + 2NaNO3. Next, calculate the molar mass of NaI to be 149.89 g/mol. Use the stoichiometry to find the moles of NaI used, then use the coefficients to find the moles of PbI2 formed. Finally, calculate the mass of PbI2 formed, knowing its molar mass is 461.01 g/mol.
