In the English language this reaction is called counter-ion exchange double displacement reaction.
through a double displacement reaction. 2Ca + Pb(NO3)4 = Pb + 2Ca(NO3)2
There is actually 6Combustion: C10H8 + 12 O2 ---> 10 CO2 + 4 H2OSynthesis: 8 Fe + S8 ---> 8 FeSDecomposition: 2 H2O ---> 2 H2 + O2Single Decomposition: Mg + 2 H2O ---> Mg(OH)2 + H2Double Decomposition: Pb(NO3)2 + 2 KI ---> PbI2 + 2 KNO3Acid Base: HBr + NaOH ---> NaBr + H2O
Potassium iodide and lead nitrate produces lead iodide and potassium nitrate its a Precipitation Reactions. 2KI+Pb(NO3)2-->PbI2 + 2KNO3
This is a solid.
Sodium Iodide is the solute which is created in the reaction and Sodium actetate solution is created. NaI + PbC2H3O2 ---> PbI (Plumbum Iodide) + NaC2H3O2 (Sodium Acetate) solution.
In the English language this reaction is called counter-ion exchange double displacement reaction.
An example of an insoluble compound formed in a double displacement reaction is a precipitate, such as silver chloride (AgCl) or lead iodide (PbI2). When two soluble ionic compounds react in a double displacement reaction, they may form an insoluble product that precipitates out of solution.
When potassium iodide is mixed with lead nitrate, a double displacement reaction occurs. The products formed are lead iodide and potassium nitrate. Lead iodide is a yellow precipitate that forms during the reaction.
Potassium iodide and lead nitrate produces golden yellow precipitate of lead iodide and potassium nitrate. This reaction is a double displacement reaction and also it can be called a precipitation reaction as lead iodide gets precipitated. 2KI+Pb(NO3)2-->PbI2 + 2KNO3
Lead(II) nitrate and sodium iodide undergo a double displacement reaction to form sodium nitrate and lead(II) iodide, which is a slightly soluble yellow solid. The balanced chemical equation for this reaction is: Pb(NO3)2(aq) + 2NaI(aq) -> 2NaNO3(aq) + PbI2(s)
The balanced equation for the reaction between lead(II) nitrate (Pb(NO3)2) and sodium iodide (NaI) to form lead(II) iodide (PbI2) and sodium nitrate (NaNO3) is: Pb(NO3)2 + 2NaI -> PbI2 + 2NaNO3
Pb(NO3)2(aq)+2NaI(aq)=2NaNO3(aq)+PbI2(s)
When lead nitrate and calcium iodide are combined, the following double displacement reaction occurs: Pb(NO3)2 + CaI2 → 2PbI2 + Ca(NO3)2. Lead iodide (PbI2) and calcium nitrate (Ca(NO3)2) are formed as the products.
The reaction between lead(II) nitrate (Pb(NO3)2) and potassium iodide (KI) is a double displacement reaction. The lead cation (Pb2+) swaps its nitrate anions (NO3-) with the potassium cation (K+) in the reactants, forming lead(II) iodide (PbI2) and potassium nitrate (KNO3).
Pb(NO3)2 + 2KI ==> PbI2 + 2KNO3 is a precipitation reaction. The PbI2 is insoluble in water and will precipitate. It is NOT neutralization, because you do not have an acid reacting with a base.
When reactants lead(II) nitrate and sodium iodide are combined, a double displacement reaction occurs. Lead(II) iodide (insoluble in water) and sodium nitrate are formed, leading to a white precipitate of lead(II) iodide and a solution of sodium nitrate.
When solutions of lead nitrate and potassium iodide are mixed, a yellow precipitate of lead iodide is formed. This reaction is a double displacement reaction where the lead from lead nitrate reacts with the iodide from potassium iodide to form the insoluble lead iodide.