In the English language this reaction is called counter-ion exchange double displacement reaction.
The reaction between potassium iodide (KI) and lead(II) nitrate (Pb(NO3)2) results in the formation of lead(II) iodide (PbI2), which is a bright yellow precipitate, and potassium nitrate (KNO3). The overall reaction can be represented as: 2KI + Pb(NO3)2 → PbI2 (s) + 2KNO3. This is an example of a double displacement reaction.
through a double displacement reaction. 2Ca + Pb(NO3)4 = Pb + 2Ca(NO3)2
There is actually 6Combustion: C10H8 + 12 O2 ---> 10 CO2 + 4 H2OSynthesis: 8 Fe + S8 ---> 8 FeSDecomposition: 2 H2O ---> 2 H2 + O2Single Decomposition: Mg + 2 H2O ---> Mg(OH)2 + H2Double Decomposition: Pb(NO3)2 + 2 KI ---> PbI2 + 2 KNO3Acid Base: HBr + NaOH ---> NaBr + H2O
Potassium iodide and lead nitrate produces lead iodide and potassium nitrate its a Precipitation Reactions. 2KI+Pb(NO3)2-->PbI2 + 2KNO3
PBI2, or lead(II) iodide, consists of one lead (Pb) atom and two iodine (I) atoms. Therefore, there are a total of three atoms in one formula unit of PBI2.
In the English language this reaction is called counter-ion exchange double displacement reaction.
An example of an insoluble compound formed in a double displacement reaction is a precipitate, such as silver chloride (AgCl) or lead iodide (PbI2). When two soluble ionic compounds react in a double displacement reaction, they may form an insoluble product that precipitates out of solution.
The reaction between potassium iodide (KI) and lead(II) nitrate (Pb(NO3)2) results in the formation of lead(II) iodide (PbI2), which is a bright yellow precipitate, and potassium nitrate (KNO3). The overall reaction can be represented as: 2KI + Pb(NO3)2 → PbI2 (s) + 2KNO3. This is an example of a double displacement reaction.
When potassium iodide is mixed with lead nitrate, a double displacement reaction occurs. The products formed are lead iodide and potassium nitrate. Lead iodide is a yellow precipitate that forms during the reaction.
Potassium iodide and lead nitrate produces golden yellow precipitate of lead iodide and potassium nitrate. This reaction is a double displacement reaction and also it can be called a precipitation reaction as lead iodide gets precipitated. 2KI+Pb(NO3)2-->PbI2 + 2KNO3
Lead(II) nitrate and sodium iodide undergo a double displacement reaction to form sodium nitrate and lead(II) iodide, which is a slightly soluble yellow solid. The balanced chemical equation for this reaction is: Pb(NO3)2(aq) + 2NaI(aq) -> 2NaNO3(aq) + PbI2(s)
The balanced equation for the reaction between lead(II) nitrate (Pb(NO3)2) and sodium iodide (NaI) to form lead(II) iodide (PbI2) and sodium nitrate (NaNO3) is: Pb(NO3)2 + 2NaI -> PbI2 + 2NaNO3
Pb(NO3)2(aq)+2NaI(aq)=2NaNO3(aq)+PbI2(s)
When lead nitrate and calcium iodide are combined, the following double displacement reaction occurs: Pb(NO3)2 + CaI2 → 2PbI2 + Ca(NO3)2. Lead iodide (PbI2) and calcium nitrate (Ca(NO3)2) are formed as the products.
The reaction between lead(II) nitrate (Pb(NO3)2) and potassium iodide (KI) is a double displacement reaction. The lead cation (Pb2+) swaps its nitrate anions (NO3-) with the potassium cation (K+) in the reactants, forming lead(II) iodide (PbI2) and potassium nitrate (KNO3).
When reactants lead(II) nitrate and sodium iodide are combined, a double displacement reaction occurs. Lead(II) iodide (insoluble in water) and sodium nitrate are formed, leading to a white precipitate of lead(II) iodide and a solution of sodium nitrate.
Pb(NO3)2 + 2KI ==> PbI2 + 2KNO3 is a precipitation reaction. The PbI2 is insoluble in water and will precipitate. It is NOT neutralization, because you do not have an acid reacting with a base.