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417.6 grams BaOH (1mol BaOH/137.3g ) = 3.042 mol
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How many moles are in 317.0 g of BaOH2?
Molar mass of barium hydroxide, Ba(OH)2 = 171.3Amount of barium hydroxide = mass of sample / molar mass = 317.0/171.3 = 1.85mol
What is the mass of 3 moles of barium?
Barium (Ba) has an At. No. of 56, and an At. Wt. of 137.36.(7.8 gm moles) X (137.36 gm/gm mole) = 1071.408 gm.
How many moles of aluminum oxide are present in a sample having a mass of 178.43g?
For this you need the atomic (molecular) mass of Al2O3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Al2O3= 102 grams408 grams Al / (102 grams) = 4.00 moles Al
How many grams of solid sodium hydroxide would need to be added to completely neutralize 35.0 mL of 1.45 M HBr?
This is a titration question: we want to have the same number of hydroxide ions as hydroxide ions so that they will form water and the pH will be neutral. In chemistry, we count atoms and molecules in moles, and we can calculate how many moles of HBr we have, because concentration in molarity is the number of moles divided by the volume in liters... M = moles/V. We plug in what we got: 1.45M = moles/0.0350L, and solve for moles: 0.0508 moles. Now we know we need 0.0508 moles of NaOH, whose molecular weight is 40g/mole. MW x moles = grams, so (40g/mole)(0.0508 moles) = 2.03 g of NaOH.
3M sodium hydroxide?
C2H4O2 + NaOH = H2O + C2H3O2Na Acetic acid (60 gm) + sodium hydroxide ( 40 gm) = 100 gm water (18 gm) + sodium acetate (82 gm) = 100 gm Ratio reactants to products = 1:1 Molarity = moles / L, 3M = 3 moles / 1 L Acetic acid = 60 gm / total reactant 100gm = 1.8 moles Multiply by 3 = 1.8 moles or 180 grams Sodium Hydroxide = 40 gm / total reactant 100 mg = 1.2 moles or 120 grams. 180 grams acetic acid + 120 grams sodium hydroxide = 300 grams. 300 grams divided by 1 liter = 3M So in order to make 3 M sodium acetate combine solution, add 180 grams acetic acid and 120 grams sodium hydroxide with 1 liter of water.
How many moles of barium are present in a sample having a mass of 22.3 grams?
# of moles = grams of substance / molar mass of substance molar mass of Barium =137.33 grams/mole #moles of Barium = 22.3 grams/ 137.33 grams/mole = 0.162382582 moles
How many moles of sodium hydroxide are in 40 grams of sodium hydroxide?
1
How many moles are in 317.0 g of BaOH2?
Molar mass of barium hydroxide, Ba(OH)2 = 171.3Amount of barium hydroxide = mass of sample / molar mass = 317.0/171.3 = 1.85mol
What is the mass in grams of 25 mol of sodium hydroxide?
It is 25 moles of Sodium Hydroxide (;
Barium hydroxide contained 2.74g in 100cm of water titration of 20cm required 18.7cm of a hydrochloric acid solution for complete neutralization what is the molarity of the barium hydroxide?
Barium Hydroxide: Mass: 2.74g. Mr = 171. Moles = Mass (g)/Mr Therefore - 2.74/ 171 = 0.01602339181mols.
How many moles are in 8 grams of sodium hydroxide?
0.2 mol
What is 83 grams of sodium hydroxide in moles?
For this you need the atomic (molecular) mass of NaOH. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaOH= 40.083.0 grams NaOH / (40.0 grams)= 2.08 moles NaOH
What is the mass of 3 moles of barium?
Barium (Ba) has an At. No. of 56, and an At. Wt. of 137.36.(7.8 gm moles) X (137.36 gm/gm mole) = 1071.408 gm.
How many moles of aluminum oxide are present in a sample having a mass of 178.43g?
For this you need the atomic (molecular) mass of Al2O3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Al2O3= 102 grams408 grams Al / (102 grams) = 4.00 moles Al
How many grams of solid sodium hydroxide would need to be added to completely neutralize 35.0 mL of 1.45 M HBr?
This is a titration question: we want to have the same number of hydroxide ions as hydroxide ions so that they will form water and the pH will be neutral. In chemistry, we count atoms and molecules in moles, and we can calculate how many moles of HBr we have, because concentration in molarity is the number of moles divided by the volume in liters... M = moles/V. We plug in what we got: 1.45M = moles/0.0350L, and solve for moles: 0.0508 moles. Now we know we need 0.0508 moles of NaOH, whose molecular weight is 40g/mole. MW x moles = grams, so (40g/mole)(0.0508 moles) = 2.03 g of NaOH.
How many grams of magnesium hydroxide required to make 1M of the solution?
the formula is no. moles is mass / molecular mass. As the number of moles is 1, the mass required will be exactly the same as the molecular mass, which is 58.32g
What is it when The number of moles of hydrogen ions equals the number of moles of hydroxide ions?
A neutral solution of about 7 pH.
