M = g/L 20 = g/0.05 20 * .05 = g 1.0 = g of solute
0.5M NaOH=Z/0.02L
Where 20mL=0.02L and Z is amount of moles
0.5M NaOH x0.02L=Z
Z=0.01 moles of NaOH
2.5
Molarity = moles of solute/Liters of solution 3.42 M NaOH = 1.3 moles NaOH/Liters NaOH Liters NaOH = 1.3 moles NaOH/3.42 M NaOH = 0.38 Liters
8 g NaOH x 1 mole NaOH/40 g = 0.2 moles NaOH
Molarity = moles of solute/Liters of solution. ( 350 ml = 0.350 Liters ) 5.7 M NaOH = moles NaOH/0.350 Liters = 1.995 moles NaOH (39.998 grams/1 mole NaOH) = 78 grams NaOH needed ------------------------------------
Moles/Liters=Molarity (M) therefore: Molarity*Liters=moles Since you were given milliliters, you must first convert your volume to liters for the equation to be accurate. 2.2M*.065L=moles=.143 moles NaOH
150 M NaOH = 150 mole / liter 20.0 mL = 0.0200 L 150 * 0.0200 = 3 moles
Molarity = moles of solute/Liters of solution ( 24.5 mL = 0.0245 L)Rearranged,moles of solute = Liters of solution * MolarityMoles NaOH = (0.0245 L)(0.130 M NaOH)= 3.19 X 10 -3 moles NaOH==================
0.75 moles in 30.0g of NaOH.
Molarity = moles of solute/Liters of solution 3.42 M NaOH = 1.3 moles NaOH/Liters NaOH Liters NaOH = 1.3 moles NaOH/3.42 M NaOH = 0.38 Liters
8 grams NaOH (1 mole NaOH/39.998 grams) = 0.2 moles NaOH
moles = mass/Mr moles = 100/(23+16+1) moles of NaOH = 2.5mol
208g NaOH
The answer is 1,668.10-4 moles.
The number of moles is 0,0038.
Molarity = moles of solute/liters of solution ( 15ml = 0.015 liters ) 2.9 M NaOH = moles NaOH/0.015 liters = 0.0435 moles of NaOH
Molecular mass of NaOH= 40.0 grams9.40 grams / (40.0 grams) = .235 moles NaOH
You need 2,4 g NaOH (0,06 moles).
The same number of moles for each.