Consider the following structure:
The name of this type is struct data_t. This means that we must include the struct keyword whenever we declare any instances of the type or declare a pointer to the type:
To remove the verbosity of the otherwise redundant structkeyword, we can use an alias:
To simplify things further, we can combine the alias with the structure's definition:
Note that the _t suffix is conventionally used to denote a user-defined type as opposed to an alias. However, its usage is not consistent. For instance, the wchar_t type is not a type, it is implemented as an alias in the
In C++, the typedef keyword is not required; it is retained purely for backward compatibility with C. Aliases are introduced with the using keyword, never with typedef. We only use typedef when we are explicitly writing code intended for compilation under both C and C++.
Note also that wchar_t (amongst others) is a built-in type in C++, so we don't need to include the C standard library to make use of it, unless we are writing code for C.
A typedef is a compiler macro. A reference is a pointer, usually implemented with transparent syntax. They have no relationship between each other.
A Macro is a preprocessor directive means that before compilation the macros are replaced. Where as typedef is defining a new data type which is same as the existing data type. Syntax: typedef Existing datatype New datatype For example typedef int NUMBER; Here NUMBER (New datatype)is defined as a data type which contains the properties same as int(Existing datatype). You can declare a variable of int as NUMBER a; is same as int a; similarly typedef int* NUMBERPOINTER; NUMBERPOINTER a; Here a is a pointer of integer type.
Yes, it is quite common. Example: struct List { struct List *Next; int value; } typedef struct List List; Example2: typedef struct Tree Tree; struct Tree { Tree *left,*right; int value; };
There will a part like this: typedef struct Point { double x, y; } Point; typedef struct LineSegment { Point from, to; } LineSegment;
Not really, but you can have: - a pointer pointing to a structure (FILE * is an example) - a pointer pointing to a structure-member (eg: struct tm tm; int *ip= &tm.tm_year) - a structure-member that is a pointer (any type) Example: typedef struct TreeNode { struct TreeNode *left, *right; int data; } TreeNode; TreeNode *root = (TreeNode *)calloc (sizeof (TreeNode), 1);
A typedef is a compiler macro. A reference is a pointer, usually implemented with transparent syntax. They have no relationship between each other.
A Macro is a preprocessor directive means that before compilation the macros are replaced. Where as typedef is defining a new data type which is same as the existing data type. Syntax: typedef Existing datatype New datatype For example typedef int NUMBER; Here NUMBER (New datatype)is defined as a data type which contains the properties same as int(Existing datatype). You can declare a variable of int as NUMBER a; is same as int a; similarly typedef int* NUMBERPOINTER; NUMBERPOINTER a; Here a is a pointer of integer type.
When you define a structure, C does not provide a type for that structure. In order to subsequently declare an instance of that structure, you need to use the word struct again. The typedef allows you to declare a type equivalent to the structure. For example... struct person { char* name, int phone}; struct person myperson; With typedef, you can simplify to... typedef struct person { char * name, int phone} person;person myperson; In C++, this is automatic, but not in C.
Yes, it is quite common. Example: struct List { struct List *Next; int value; } typedef struct List List; Example2: typedef struct Tree Tree; struct Tree { Tree *left,*right; int value; };
There will a part like this: typedef struct Point { double x, y; } Point; typedef struct LineSegment { Point from, to; } LineSegment;
It means a structure has a member that is an array: typedef struct foo { int x[42]; // an array of 42 integers // other members... };
Not really, but you can have: - a pointer pointing to a structure (FILE * is an example) - a pointer pointing to a structure-member (eg: struct tm tm; int *ip= &tm.tm_year) - a structure-member that is a pointer (any type) Example: typedef struct TreeNode { struct TreeNode *left, *right; int data; } TreeNode; TreeNode *root = (TreeNode *)calloc (sizeof (TreeNode), 1);
Typecasting is to make a variable of one type, act like another type for one single operation. Type-def is to assign alternative names to existing types.
No, but 'typedef int a;' is possible, it defines the type 'a'.
the purpose of typedef is to redefine the name of an existing variable type. e.g. typedef unsigned long int T; T v1,v2;
typedef struct ListElement {struct ListElement *next;long data;} ListElement;
Its very Simple that using Enumerated data type you are making special integers that flow within range, While a typedef is redefining data type with new name. Example: like defining enum Days{sun,mon,tue.....} makes an integer definition that can have 0-7 values So if u do following: Days x=sun; or Days x=0; then x=x+2; is 2 or tue and x=x+7; is 0 or sun again... Means its modulo 7 data type ................. While doing this: typedef Days WeekDays; renames Days as WeekDays Similary typedef int NUMBER; renames int as NUMBER .But wait it is one more name for the data type.. So simply enum creates a numeral modular datatype with a range while typedef creates another name for it. Rupesh K Joshi