0.330 moles of calcium has a mass of 13.2 grams.
CaCO3, or calcium carbonate, has a molar mass of 100.09 grams per mole. This means there are roughly 566 grams of CaCO3.
(g) -> moles = x(g) * (1 mol/molar mass)Moles -> atoms = x(mol) * (6.022*10^23/1 mol)
Use the equationmol = mass / RFM (or RAM)mol = 37 / (40 + 16x2 + 1x2)mol = 37 / 74mol = 0.5
mol = mass/Mr mol x Mr = mass Mr of tungsten is 183.84 so 1.2 x 183.84 = 220.61g
The mass in grams of 1,40 mol of anhydrous iron(III) sulfate is 559,832.
The mass is 0.330 mol Ca (40.08 g/mol) = 13.2 g Ca
From the periodic table, calcium has a molar mass of 40.078g/mol and sulfur has a molar mass of 32.065g/mol. The formula for compound formed from calcium and sulfur, calcium sulfide is CaS. The molar mass of CaS is 72.143. So, if you round the numbers, 40g of Ca + 32g of S will produce 72g of CaS.
To calculate the number of moles in a sample, divide the mass of the sample by the molar mass of the compound. The molar mass of calcium sulfate is calculated by adding the atomic masses of calcium, sulfur, and four oxygen atoms: Ca = 40.08 g/mol S = 32.06 g/mol O = 16.00 g/mol Molar mass of calcium sulfate = (40.08 g/mol) + (32.06 g/mol) + (4 × 16.00 g/mol) = 136.14 g/mol Now we can calculate the number of moles in 54.0 grams of calcium sulfate: Number of moles = mass (g) / molar mass (g/mol) = 54.0 g / 136.14 g/mol = 0.397 moles (rounded to three decimal places)
CaCO3, or calcium carbonate, has a molar mass of 100.09 grams per mole. This means there are roughly 566 grams of CaCO3.
For this you need the atomic (molecular) mass of CaCO3. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. CaCO3= 100.1 grams2.50 moles CaCO3 × (100.1 grams) = 250.25 grams CaCO3
The mass in grams of 5,01 mol of xenon is 657,778 g.
(g) -> moles = x(g) * (1 mol/molar mass)Moles -> atoms = x(mol) * (6.022*10^23/1 mol)
The formula is CaF2 so, its three atoms, one calcium and two fluorine atoms. add the molar mass of calcium(40 g/mol) and fluorine(19 g/mol X 2 because there are two atoms of fluorine) and you get 40+(19x2)=78 78 grams per mol
450.3915Calcium Carbonate (CaCO3) has a molar mass of 100.087 g/mol.4.5 mol * 100.087 g/mol = 450.3915 (because the mol's cancel leaving you with grams)
Use the equationmol = mass / RFM (or RAM)mol = 37 / (40 + 16x2 + 1x2)mol = 37 / 74mol = 0.5
molar mass CaCO3= 100g/m 100 x 0.250= 25 g
mol = mass/Mr mol x Mr = mass Mr of tungsten is 183.84 so 1.2 x 183.84 = 220.61g