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What is the mass in grams of 4.80 x 1023 formula units of iron III nitrate?
Wiki User
∙ 11y ago
6.023 x 1023 molecules of iron(III) nitrate weigh 241.86 g
So, 4.80 x 1023 molecules will weigh 192.75 g
Wiki User
∙ 11y ago
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How many moles are in 2.9 x 1021 formula units of NaCl?
1 mole NaCl = 6.022 x 1023 formula units NaCl 2.9 x 1021 formula units NaCl x 1mol NaCl/6.022 x 1023 formula units NaCl = 0.0048 mole NaCl
How many formula units are in .671 moles of iron III sulfate?
1 mole Fe2(SO4)3 = 6.022 x 1023 formula units Fe2(SO4)3 0.671mol Fe2(SO4)3 x 6.022 x 1023 formula units Fe2(SO4)3/1mol Fe2(SO4)3 = 4.04 x 1023 formula units Fe2(SO4)3
How many molecules are in LiCi are in a 127.17 g sample?
1 mole LiCl = 42.394g = 6.022 x 1023 formula units (not molecules because it is ionic) 127.17g LiCl x 6.022 x 1023 formula units/42.394g = 1.8064 x 1024 formula units
What is the mass of 9.871023 formula units of aluminum oxide?
Assuming that the number "9.871023" would or should have been written as "9.87 X 1023" if the typographical resources to do so were available to the questioner: Avogadro's Number, which is the number of formula units in a mole of any material, is about 6.022 X 1023. The gram formula mass for aluminum oxide is 101.96. Therefore, the mass of the stated number of formula units of aluminum oxide is: 101.96(9.87/6.022) or about 164 grams, to the justified number of significant digits.
How many molecules would be found in 427.4 grams of potassium nitrate?
Quite a few! 427.4 grams KNO3 (1 mole KNO3/101.11 grams)(6.022 X 1023/1 mole KNO3) = 2.546 X 1024 molecules of potassium nitrate -----------------------------------------------------------
How many formula units in 3.6 grams of NaCl?
1 mole NaCl = 58.443g NaCl = 6.022 x 1023 formula units NaCl 3.6g NaCl x 1mol NaCl/58.443g NaCl x 6.022 x 1023 formula units NaCl/mol NaCl = 3.7 x 1022 formula units NaCl
How many molecules are in 7.4 g H'S?
By definition, Avogadro's Number is the number of molecules or formula units in the number of grams corresponding to the gram molecular weight or gram formula unit, and by experiment, Avogadro's Number is about 6.022 X 1023. Therefore, 7.75 X 1025 formula units contains (7.75 X 1025/6.022 X 1023) or 1.29 X 102 moles or formula units, to the justified number of significant digits.
How do you Convert 1.18 gram to atomic mass unit?
1 gram = 6.0221415 × 1023 atomic mass units, so multiply grams by 6.0221415 × 1023 1.18 grams = 7.10612697 × 1023 atomic mass units
Grams to formula units?
It depends on the substance and its molar mass.In order to convert from grams to formula units, you must first convert grams to moles, then moles to formula units (grams --> moles --> formula units).1. Divide the mass (g) of the given substance by the substance's molar mass.2. Multiply the number of moles found in Step 1 (above) by Avogadro's number (6.022 x 1023).---- Mass substance ----- X 6.022 x 1023 formula unitsMolar mass substanceCONVERSION FACTORMass (g) substance x 1 mol substance ------- x ----- Avogadro's number/////////////////// molar mass (g) substance ------------ 1 mol substance
How many formula units in 47.63 grams?
It depends on the substance and its molar mass.In order to convert from grams to formula units, you must first convert grams to moles, then moles to formula units (grams --> moles --> formula units).1. Divide the mass (g) of the given substance by the substance's molar mass.2. Multiply the number of moles found in Step 1 (above) by Avogadro's number (6.022 x 1023).---- Mass substance ----- X 6.022 x 1023 formula unitsMolar mass substanceCONVERSION FACTOR47.63g substance x 1 mol substance ---- x ----- Avogadro's number///////////////////// molar mass (g) substance ////// 1 mol substance
How many grams of sodium chloride are in 3 x 10 to the 25 formula units of sodium chloride?
1 mole NaCl = 58.443g NaCl = 6.022 x 1023 formula units NaCl 3 x 1025 formula units NaCl x 1mol NaCl/6.022 x 1023 formula units NaCl x 58.443g NaCl/mol NaCl = 2911g NaCl = 3000g NaCl (rounded to 1 significant figure)
How many moles are in 2.9 x 1021 formula units of NaCl?
1 mole NaCl = 6.022 x 1023 formula units NaCl 2.9 x 1021 formula units NaCl x 1mol NaCl/6.022 x 1023 formula units NaCl = 0.0048 mole NaCl
How many moles of CaCl2 contain 1.26x1024 formula units of CaCl2?
1 mole CaCl2 = 6.022 x 1023 formula units CaCl2 1.26 x 1024 formula units CaCl2 x 1mol CaCl2/6.022 x 1023 formula units CaCl2 = 2.09 moles CaCl2
What mass of sodium chloride contains 4.59 exp24 formula units?
The gram formula unit mass of sodium chloride is 58.443, and every gram formula unit mass contains Avogadro's Number, 6.022 X 1023 formula units. Therefore, the mass sought is 58.443 X (4.59 X 1024)/(6.022 X 1023) or 445 grams, to the justified number of significant digits.
How many formula units are in .671 moles of iron III sulfate?
1 mole Fe2(SO4)3 = 6.022 x 1023 formula units Fe2(SO4)3 0.671mol Fe2(SO4)3 x 6.022 x 1023 formula units Fe2(SO4)3/1mol Fe2(SO4)3 = 4.04 x 1023 formula units Fe2(SO4)3
How many molecules are in LiCi are in a 127.17 g sample?
1 mole LiCl = 42.394g = 6.022 x 1023 formula units (not molecules because it is ionic) 127.17g LiCl x 6.022 x 1023 formula units/42.394g = 1.8064 x 1024 formula units
What is the mass of 9.871023 formula units of aluminum oxide?
Assuming that the number "9.871023" would or should have been written as "9.87 X 1023" if the typographical resources to do so were available to the questioner: Avogadro's Number, which is the number of formula units in a mole of any material, is about 6.022 X 1023. The gram formula mass for aluminum oxide is 101.96. Therefore, the mass of the stated number of formula units of aluminum oxide is: 101.96(9.87/6.022) or about 164 grams, to the justified number of significant digits.
