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Add individual masses (rounded) for gram formula mass.
K= 39 O= 16 H= 1 39+16+1= 56
Find number of moles = 4.5
Multiple gram formula mass and the number of moles
56*4.5 = 252g
^Answer
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How many milliliters of 0.103 M HCl would be required to titrate 6.46 g KOH?
6.46g(KOH) / 56.108 g/mol(KOH) = 0.1151 mol(KOH) = 0.1151 mol(OH-) , which needs of the titrant the same amount of acid, so:0.1151 mol H+ = 0.1151 mol(HCl) / 0.103 mol(HCl)/L(titrant) = 1.118 L of this titrant ( 0.103 M HCl)= 1118 ml
What is the molar mass of KOH?
molar mass is the mass of one mole of a substance. A mole is an amount, refers to Avogadros number which is 6.022 x 1023. a mole of atoms is that many atoms. therefore the molar mass of potassium hydroxide KOH is the mass of that many molecules of KOH. On the periodic table the mass number for each element is molar, so all you need to do is add together the molar mass of each element in the compound. Molar mass of potassium (K) is 39 Molar mass of oxygen (O) is 16 Molar mass of hydrogen (H) is 1 There is one of each of these elements in a molecule of potassium hydroxide therefore the molar mass = 39 + 16 + 1 = 56
How many moles are in 234.1 grams of KOH?
Molar mass of KOH = 39.1+16.0+1.0 = 56.1Amount of KOH = mass of sample / molar mass = 32/56.1 = 0.570mol
What is the Gibbs free energy of KOH?
Del G of KOH = -379.07 Kj/mol hope it is of some use
What equation shows how to calculate how many grams g of KCl would be produced from 4 mol KOH The balanced reaction is MgCl2 plus 2KOH Mg OH 2 plus 2KCl?
4mol KOH x 1 mol Mg(OH)2 x 58.31g Mg(OH) 1 2 mol KOH 1 mol Mg (OH)2
How many moles are in 35.28 g of koh?
35.28 (g) / 56.1056 (g/mol) = 0.6288 mol KOH
How many milliliters of 0.103 M HCl would be required to titrate 6.46 g KOH?
6.46g(KOH) / 56.108 g/mol(KOH) = 0.1151 mol(KOH) = 0.1151 mol(OH-) , which needs of the titrant the same amount of acid, so:0.1151 mol H+ = 0.1151 mol(HCl) / 0.103 mol(HCl)/L(titrant) = 1.118 L of this titrant ( 0.103 M HCl)= 1118 ml
What is the molar mass of KOH?
molar mass is the mass of one mole of a substance. A mole is an amount, refers to Avogadros number which is 6.022 x 1023. a mole of atoms is that many atoms. therefore the molar mass of potassium hydroxide KOH is the mass of that many molecules of KOH. On the periodic table the mass number for each element is molar, so all you need to do is add together the molar mass of each element in the compound. Molar mass of potassium (K) is 39 Molar mass of oxygen (O) is 16 Molar mass of hydrogen (H) is 1 There is one of each of these elements in a molecule of potassium hydroxide therefore the molar mass = 39 + 16 + 1 = 56
A certain pain reliever was analyzed for aspirin by dissolving 250 mg of the tablet in water and titrating with .0300M KOH Titration required 29.40 mL of base What is percentage by weight of aspirin?
HC9H7O4+KOH--> [C9H7O4]-K+ +H2O moles of KOH= 0.300mol/L x 0.0294L =8.82x10^-4 mol KOH 1 mole of KOH=1 mole of HC9H7O4 moles of HC9H7O4= 8.82x10^-4 mol mass of aspirin= 8.82x10^-4 mol x 180.09 g/mol = 0.15884 g 250mg=0.25g %weight= (weight of solute/weight of sample) x 100% = ( 0.15884g/0.25g) x 100% =63.54% of aspirin
How many moles are in 234.1 grams of KOH?
Molar mass of KOH = 39.1+16.0+1.0 = 56.1Amount of KOH = mass of sample / molar mass = 32/56.1 = 0.570mol
What is the Gibbs free energy of KOH?
Del G of KOH = -379.07 Kj/mol hope it is of some use
What equation shows how to calculate how many grams g of KCl would be produced from 4 mol KOH The balanced reaction is MgCl2 plus 2KOH Mg OH 2 plus 2KCl?
4mol KOH x 1 mol Mg(OH)2 x 58.31g Mg(OH) 1 2 mol KOH 1 mol Mg (OH)2
What is KOH's weight?
K - 39.10O - 16.00H - 1.01---- = 56.11 g/mol!Just add the three individual atomic masses together to get the molecular mass. Hope this helps.
What is the mass of 0.7891 mol of ferric oxide (Fe2O3)?
Atomic Mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
How many moles of KOH are contained in 750. mL of 5.00 M KOH solution?
Molarity = moles of solute/volume of solution 0.500 M KOH = moles KOH/125 ml 62.5 millimoles, or to answer the question precisely, 0.0625 moles KOH
How many potassium hydroxide (KOH) formula units are present in 6.89 mol of KOH?
I mol contains 6.023 x 10 e 23. So the answer is 6.89 times that, or 4.149847 x 10 e 24.
What is KOH Molecular weight?
K - 39.10O - 16.00H - 1.01---- = 56.11 g/mol!Just add the three individual atomic masses together to get the molecular mass. Hope this helps.
