Want this question answered?
# moles = mass / molar mass = 1.23g / 83.80g/mol =1.47x10^-2 moles There are 1.47x10^-2 moles in 1.23g of krypton
The mass in grams of 5,01 mol of xenon is 657,778 g.
1.9 mol Se ( 78.96 grams/1mol Se ) = 150.024 grams
The mass of phosphorus of any sample of calcium phosphate is the mass of the same multiplied by the percentage that phosphorus makes up of that sample. (mass of sample) x (mass of phosphorus/total mass) Therefore we must look at the chemical formula of the substance in question: Ca3(PO4)2. From this we can see that there are 2 phosphorus atoms attributing mass to the total molecule. The formula becomes: 500 g x 2x30.97 g/mol/310.17 g/mol = 99.8 g molar mass of phosphorus: 30.97 g/mol molar mass of calcium phosphate: 310.17 g/mol total mass: 500 g
The answer is 319,15 g.
# moles = mass / molar mass = 1.23g / 83.80g/mol =1.47x10^-2 moles There are 1.47x10^-2 moles in 1.23g of krypton
The mass in grams of 5,01 mol of xenon is 657,778 g.
mol = mass/Mr mol x Mr = mass Mr of tungsten is 183.84 so 1.2 x 183.84 = 220.61g
1.9 mol Se ( 78.96 grams/1mol Se ) = 150.024 grams
The mass in grams of 1,40 mol of anhydrous iron(III) sulfate is 559,832.
The mass of phosphorus of any sample of calcium phosphate is the mass of the same multiplied by the percentage that phosphorus makes up of that sample. (mass of sample) x (mass of phosphorus/total mass) Therefore we must look at the chemical formula of the substance in question: Ca3(PO4)2. From this we can see that there are 2 phosphorus atoms attributing mass to the total molecule. The formula becomes: 500 g x 2x30.97 g/mol/310.17 g/mol = 99.8 g molar mass of phosphorus: 30.97 g/mol molar mass of calcium phosphate: 310.17 g/mol total mass: 500 g
0.330 moles of calcium has a mass of 13.2 grams.
Carbon tetraflouride or CF4, has a molar mass of 88.004 grams per mol. 1.32 mols of CF4 then has a mass of 116 grams
The mass of 2.000 mol of oxygen atoms is 32.00 grams.
578
The answer is 399 grams
The answer is 69.7247149193