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What is the maximum volume of 0.10 m naoh that can be completely neutralized by 0.20 ml of hcl?
Wiki User
∙ 11y ago
50. mL
Wiki User
∙ 11y ago
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Does HCl change in concentration when neutralized with NaOH?
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How do you prepare 0.5N NaOh?
Take half volume of 1.0 M NaOH and add another half volume of water. Or Take 20.0 gram NaOH , carefully dissolve this completely in ca. 0.9 L water and then fill up to 1.0 L end volume.
How many grams of solid NaOH are needed to prepare 500mL NaOH solution with a concentration of 0.4M?
molarity equals moles of solute /volume of solution in litres . moles of NaOH equals 5g/40g = 0.125 and volume of solution will be volume of water + volume of NaOH = 0.5 litre+0.002 l which is nearly 0.5 litre . (volume of NaOH is calculated by its density) so molarity = 0.125mol/0.5litre = 0.25 M
A nitric acid solution is neutralized using sodium hydroxide How many grams of sodium hydroxide are needed to neutralize 2.50 L of 0.800 M nitric acid solution?
Make sure that the equation is balanced. NaOH + HNO3 > > NaNO3 + H2O ( all one to one ) 15.0 grams NaOH (1mol NaOH=39.998g) (1mol HNO3/1mol NaOH) = 0.375 moles of HNO3 Molarity = mols solute/volume solution 2.00M HNO3 = 0.375 mols/X volume = 0.188 Liters or, 188 milliliters.
What is the Amount of benzoic acid to be neutralized by 20 mL NaOH solution in both moles and grams?
We need to know the Molarity (or Molality or formality) of both the acid and the NaOH solution in order to answer this question.
Does HCl change in concentration when neutralized with NaOH?
fap
How do you prepare 0.5N NaOh?
Take half volume of 1.0 M NaOH and add another half volume of water. Or Take 20.0 gram NaOH , carefully dissolve this completely in ca. 0.9 L water and then fill up to 1.0 L end volume.
How do you dissolve phenol crystals?
Phenol is a strong acid so it may be neutralized by any base as NaOH
How many grams of solid NaOH are needed to prepare 500mL NaOH solution with a concentration of 0.4M?
molarity equals moles of solute /volume of solution in litres . moles of NaOH equals 5g/40g = 0.125 and volume of solution will be volume of water + volume of NaOH = 0.5 litre+0.002 l which is nearly 0.5 litre . (volume of NaOH is calculated by its density) so molarity = 0.125mol/0.5litre = 0.25 M
A nitric acid solution is neutralized using sodium hydroxide How many grams of sodium hydroxide are needed to neutralize 2.50 L of 0.800 M nitric acid solution?
Make sure that the equation is balanced. NaOH + HNO3 > > NaNO3 + H2O ( all one to one ) 15.0 grams NaOH (1mol NaOH=39.998g) (1mol HNO3/1mol NaOH) = 0.375 moles of HNO3 Molarity = mols solute/volume solution 2.00M HNO3 = 0.375 mols/X volume = 0.188 Liters or, 188 milliliters.
What is the Amount of benzoic acid to be neutralized by 20 mL NaOH solution in both moles and grams?
We need to know the Molarity (or Molality or formality) of both the acid and the NaOH solution in order to answer this question.
27.0 ml of 0.45 m naoh is neutralized by 20 ml of an hcl solution the molarity of the hcl solution is?
Given: 27 mL of NaOH, 0.45M; 20 mL HCI Need: M of HCI 27 ml NaOH*(1 L NaOH/1000mL NaOH)*(0.45M NaOH/1L NaOH)*(1mole HCI/1 mole NaOH)=0.012 0.012/0.02=0.607 M HCI (or rounded 0.61 M HCI)
What happenes when the active ingredients of acid and basis together?
A neutralization reaction. NaOH + HCl -> NaCl + H2O Neutralized and the products are a salt and water.
Can a base be neutralized by a hydroxide if not why?
Hydroxide compounds such as sodium hydroxide (NaOH) are bases. Bases do not neutralize other bases. Acids neutralize bases.
A nitric acid soulution is neutralized using sodium hydroxide how many grams of sodium hydroxide are needed to neutralize 2.50 L of 0.800 M Nitriric acid soulution?
Balanced equation first. HNO3 + NaOH >> NaNO3 + H2O Now, Molarity = moles of solute/volume of solution ( find moles HNO3 ) 0.800 M HNO3 = moles/2.50 Liters = 2 moles of HNO3 ( these reactants are one to one, so we can proceed to grams NaOH ) 2 moles NaOH (39.998 grams NaOH/1mole NaOH) = 79.996 grams of NaOH need to neutralize the acid. ( you do significant figures )
How much NaOH should be weighed out in order to make a 1 M solution?
You need 40.01 g NaOH per liter volume of the solution. This is not the same as adding 1 liter of water to 40.01 g of NaOH. The NaOH must be put in the flask and the volume brought up to 1 liter total volume (NaOH volume + water volume).
What volume of NaOH was used in the titration?
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