Chemistry

# What is the molarity of 6 moles of NaCl dissolves in 2 L of water?

012 ###### 2017-06-19 17:23:37

Molarity is defined as moles solute/liter of solution6 moles/2 liters solution = 3 molar

NOTE: This assumes no volume change and 2L is the final volume of solution.

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## Related Questions Molarity = moles of solute/Liters of solution Molarity = 6 Moles NaCl/2 Liters = 3 M NaCl ======== Molarity = moles of solute/volume of solution Find moles NaCl 55 grams NaCl (1mol NaCl/58.44 grams) = 0.941 moles NaCl Molarity = 0.941 moles NaCl/35 Liters = 0.027 Molarity NaCl ( sounds reasonable as 55 grams is not much in 35 Liters of water, which would be about 17.5 2 liter sodas )  Find moles NaCl first.14.60 grams NaCl (1 mole NaCl/58.44 grams)= 0.2498 moles NaCl================Now,Molarity = moles of solute/Liters of solutionMolarity = 0.2498 moles NaCl/2.000 Liters= 0.1249 M NaCl solution--------------------------------  Molarity = moles of solute/Liters of solution Find moles NaCl 300 grams NaCl (1 mole NaCl/58.44 grams) = 5.13347 moles NaCl Molarity = 5.13347 moles NaCl/3000 Liters = 1.71 X 10^-3 M sodium chloride ---------------------------------------- Molarity = moles of solute/Liters of solution Find moles NaCl 9 grams NaCl (1 mole NaCl/58.44 grams) = 0.154 moles NaCl Molarity = 0.154 moles NaCl/1 Liter = 0.2 M sodium chloride ------------------------------- Molarity = moles of solute/Liters of solutionGet moles NaCl.58.44 grams NaCl (1 mole NaCl/58.44 grams)= 1 mole NaCl------------------Molarity = 1 mole NaCl/1 liter= 1 M NaCl======== Molarity = moles of solute/Liters of solution Molarity = 0.250 moles NaCl/2.25 Liters = 0.111 M NaCl --------------------  Get moles NaCl and change 245 ml to 0.245 Liters. 3.8 grams NaCl (1 mole NaCl/58.54 grams) = 0.0650 moles NaCl Molarity = moles of solute/Liters of solution Molarity = 0.0650 moles NaCl/0.245 Liters = 0.27 M NaCl ---------------------- Molarity = moles of solute/Liters of solutionMoles of solute = Liters of solution * Molarity ( 100 mL = 0.1 Liters )Moles of NaCl = 0.1 Liters * 0.20 M NaCl= 0.02 moles NaCl============  Molarity = moles of solute/Liters of solution ( 300 ml = 0.300 Liters ) For our purposes, Moles of solute = Liters of solution * Molarity Moles NaCl = 0.300 Liters * 0.15 M = 0.05 moles NaCl ============= Pretty concentrated! ( I assume you mean 2.3 Liters )First get the moles of sodium chloride.456 grams NaCl (1 mole NaCl/58.44 grams)= 7.803 moles NaCl==============Now,Molarity = moles of solute/Liters of solutionMolarity = 7.803 moles NaCl/2.3 Liters= 3.4 M NaCl solution---------------------------- Molarity = moles of solute/Liters of solution 3.45 M NaCl = moles NaCl/5 liters = 17.25 moles  volume given =27.5mlmolarity of base=0.105find number of moles=moles=vol(cm3)/1000*molarity of NaClmoles=27.5/1000*0.105=3.82 moles of sodium chloride Molarity = moles of solute/volume of solution so, 125 grams of NaCl (1mol NaCl/58.44 grams NaCl) = 2.1389 moles NaCl/400 Liters = 0.00535 M NaCl Molarity = moles solute/liter solutionmoles solute = 7 g NaCl x 1 mol NaCl/58 g NaCl = 0.12 moles NaClliters of solution = 450.0 ml x 1 L/1000 ml = 0.450 litersmolarity = 0.12 moles/0.450 liters = 0.268 M = 0.3 M (one sig fig) Need moles NaCl first. 17.52 grams NaCl (1 mole NaCl/58.44 grams) = 0.29979 moles NaCl =====================Now. Molarity = moles of solute/Liters of solution ( 2000 ml = 2 Liters ) Molarity = 0.29979 mole NaCl/2 Liters = 0.1499 M NaCl ---------------------- I assume you mean 174 grams NaCl. Be careful with units, decimal points and amounts as we are not mind readers here and I could be wrong about this assumption. Regardless, need moles NaCl first.174 grams NaCl (1 mole NaCl/58.44 grams)= 2.977 moles NaCl=================now,Molarity = moles of solute/Liters of solutionMolarity = 2.977 moles NaCl/4.00 Liters= 0.744 M NaCl solution------------------------------- Need to find moles NaCl. 526 grams NaCl (1 mole NaCl/58.44 grams) = 9.0 moles NaCl --------------------------------now, Molarity = moles of solute/Liters of solution or, for our purposes Liters of solution = moles of solute/Molarity Liters of solution = 9.0 moles NaCl/3.0 M = 3.0 liters in volume --------------------------------- Molarity = moles of solute/liters of solution ( 50 ml = 0.05 liters ) 2.50 Molar NaCl = moles NaCl/0.05 liters solution = 0.125 moles NaCl ( 7.305 grams NaCl ) Molarity = moles of solute/Liters of solution ( find the moles ) 2.36 M NaCl = moles NaCl/5.08 Liters NaCl = 12.0 moles

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