Acids and Bases

# What is the molarity of a 3000 liters solution containing 300 grams of NaCl?

###### Wiki User

Molarity = moles of solute/Liters of solution

Find moles NaCl

300 grams NaCl (1 mole NaCl/58.44 grams) = 5.13347 moles NaCl

Molarity = 5.13347 moles NaCl/3000 Liters

= 1.71 X 10^-3 M sodium chloride

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## Related Questions

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