39.997 g mol-1
To find the number of moles in 9.4 g of NaOH, you first need to calculate the molar mass of NaOH (22.99 g/mol for Na, 15.999 g/mol for O, and 1.008 g/mol for H). Add these together to get 39.997 g/mol for NaOH. Next, divide the given mass by the molar mass to get the number of moles: 9.4 g / 39.997 g/mol ≈ 0.235 moles of NaOH.
For this you need the atomic (molecular) mass of NaOH. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaOH= 40.083.0 grams NaOH / (40.0 grams)= 2.08 moles NaOH
to solve this you must have the molecular weight of NaoH and you can get this by add the molar masses together (H=1 , O=16 , Na-23 ) then multiply the no of moles by the molecular mass that is for mole gram conversion so you have (23+16+1)= 40 and already you have multiplied (2.40)=80 then 2 . 40 = 120 then 80 / 40 = 2 the answer is 2
The a.m.u. is defined as the fraction of 1/12 of an atom of the carbon-12 isotope. The value is pretty nearer to the mass of a hydrogen atom. Therefore, in every compound, the gram molecular weight is numerically equal to the molecular mass in atomic mass units. Therefore the gram molecular weight of NaOH is 40 g/mol.
3.42 moles NaOH (39.998 grams/1 mole NaOH) = 137 grams NaOH
To find the number of moles of NaOH in 25.0 g, you first need to determine the molar mass of NaOH (40.00 g/mol). Then, divide the given mass by the molar mass to get the number of moles: 25.0 g / 40.00 g/mol = 0.625 mol of NaOH.
To do this, you need to know the molecular weight of the element you're dealing with, by adding up the atomic weights of the elements involved (found on any periodic table). The molecular weight is the mass in grams of the compound in one mole - this will provide you with a conversion factor. So take the measurement in grams and divide it by the molecular weight to convert to moles. Really what you're doing is multiplying the number by 1 mole, and dividing it by the equivalent of one mole, the molecular weight. That's the thought process behind unit analysis and how you get your "units to cancel".In this case, the answer is about 2 grams NaOH.
First, find the molecular weights of the individual elements. Next, multiply each of the weights of the individual elements in the NaOH. Next, sum the molecular weights. What does the resulting number give you? That is, what does it express? Does it provide one of the entities needed to determine molarity? Next, determine how many 250-ml volumes are in a liter. You now have the two entities necessary to calculate the answer to your question. Hop to it.
The molar mass of NaOH (sodium hydroxide) is approximately 40 g/mol.
The molar mass of sodium hydroxide (NaOH) is approximately 40 g/mol. To find the mass of 2.75 moles of NaOH, you would multiply the number of moles by the molar mass: 2.75 moles x 40 g/mol = 110 grams.
Na + O + H = ? 22.99 +16.00+1.01= 40 this is easily found with any compound, just add their molar masses up. If there are elements that are present which you have more than one of just multiply its mass by that number.
The molarity of NaOH solution is 0.010 mol/L. To find the mass, you need to multiply the molarity by the molar mass of NaOH. The molar mass of NaOH is approximately 40 g/mol. Therefore, the mass of NaOH in 2.5 L of 0.010 M solution is 1 g.