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NaCl (gmw=58g, valence=1)

Grams of equivalent weight = 58/1 = 58grams

so 1EQ/ 58grams=1

Normality is expressed in Eq/L

With 1% defined as 1 gram per 100 ml, 85% is 85 grams per 100 ml

(1EQ/58grams) * (85grams/100ml) * (1000ml/L) = 85000eq/5800L = 14.655 or 15N

Although I don't think you were supposed to do 85%, for clinical chemistry it should be something more like 0.85% or the solution would be too hypertonic. In which case it would be

(1eq/58grams)*(0.85grams/100ml)* (1000ml/L) = 850eq/5800L = 0.14655 or 0.15N

FG 9/16/2012

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Q: What is the normality of isotonic saline 85 percent NaCL?
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