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What is the number of moles of NaOH required to neutralize 1 mole of H2SO4?
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How many moles of sodium hydroxide are required to neutralize 20 mol of nitric acid?
20 moles of NaOH needed to neutralize 20 moles of nitric acid
What volume (in liters) of a 1.9 M NaOH solution would neutralize 7.2 moles of H2SO4 (diprotic)?
The answer is 7,66 L.
What is the number of moles os H2SO4 in 100mL of 12M H2SO4 solution?
The answer is 1,2 mol.
What is the total number of moles of H2SO4 needed to prepare 5.0 liters of a 2.0 M solution of H2SO4?
The answer is 0,526 mL.
How many moles are in 3.4 10 to the power of 23 molecules of H2SO4?
Simply divide by the number that signifies moles of any thing; Avogadro's number. 3.4 X 10^23/6.022 X 10^23 = 0.56 moles of H2SO4
How many moles of sodium hydroxide are required to neutralize 20 mol of nitric acid?
20 moles of NaOH needed to neutralize 20 moles of nitric acid
What volume (in liters) of a 1.9 M NaOH solution would neutralize 7.2 moles of H2SO4 (diprotic)?
The answer is 7,66 L.
What is the number of moles os H2SO4 in 100mL of 12M H2SO4 solution?
The answer is 1,2 mol.
What is the total number of moles of H2SO4 needed to prepare 5.0 liters of a 2.0 M solution of H2SO4?
The answer is 0,526 mL.
How many moles are in 3.4 10 to the power of 23 molecules of H2SO4?
Simply divide by the number that signifies moles of any thing; Avogadro's number. 3.4 X 10^23/6.022 X 10^23 = 0.56 moles of H2SO4
If 25.0 ml of 1.48m h2so4 can be neutralized with 27.29 ml of koh what is the molarity of the koh?
25 milliliters of the solution has . 037 moles of H2SO4. The neutralization reaction is H2SO4 + 2 KOH yields 2 H2O + K2SO4. So, . 074 moles of KOH are required. This equals 2. 71 mL of solution.
How many hydrogen atoms are in 0.09 moles of H2SO4 Please explain as well?
Just moles against the ratio of hydrogen atoms in compound then against Avogadro's number. Like this 0.09 moles H2SO4 (2 moles H/1 mole H2SO4)(6.022 X 10^23/1 mole H) = 1.1 X 10^23 hydrogen atoms
How many moles of sulfur are present in 5 moles of H2So4?
5 moles
How many moles of which reactant are in excess when 359.0 mL of 0.259 M sulfuric acid reacts with 0.510 L of 0.191 M sodium hydroxide to form water and aqueous sodium sulfate?
Balanced equation first. 2NaOH + H2SO4 -> Na2SO4 +2H2O Molarity = moles of solute/Liters of solution 0.259 M H2SO4 = moles H2SO4/0.359 liters = 0.09298 moles H2SO4 0.191 M NaOH = moles of NaOH/0.510 liters = 0.09741 moles NaOH ( Let us find limiting reactant ) 0.09298 moles H2SO4 (1 mole H2SO4/2 mole NaOH) = 0.04649 moles H2SO4-- Sulfuric acid limits and, 0.04648 moles of sodium hydroxide are in excess.
The molecular mass of 2 moles in H2SO4?
2 moles H2SO4 (98.086 grams/1 mole H2SO4)= 196.172 grams of sulfuric acid====================
How many times do you have to neutralizer bases using an acid?
The number of moles of acid and the base should be equal to neutralize. (So the number of moles of base is needed to answer this correctly)
How many molecusles are contained in 55.0 g of H2SO4?
how many molecules are containd in 55.0g of H2SO4
