0
What is the power dissipated by a 9 ohm resistor with 3 amps flowing through it?
Wiki User
∙ 11y ago
Here are a few easy and related equations.
V = Voltage, I = Current (amps)
R = Resistance, (Ohms)
V = I X R
R= V / I
I = V / R
Power = Watts = W, is expressed as V X I. Since V =I X R, W then also = R X I X I
Which is I **2 X R
Same as V**2 / R
So, if your I = 3 and your R = 3, and because I X R = V,
3 X 3 =9 Volts
(Note: capacitance and inductance can also influence the amount of current flow in a system. This resistance is referred to as reactance. Both reactances are a function of the frequency of the Voltage applied.)
Have a wonderful day. Bob
Wiki User
∙ 10y ago
Wiki User
∙ 14y agoNine volts across three ohms yields three amperes.
Ohm's law: Voltage equals current times resistance.
Wiki User
∙ 8y agoIn a DC circuit, V=IR
Therefore, the current I will be 27V
Wiki User
∙ 14y agoUse Ohms Law: voltage = current x resistance.
Wiki User
∙ 8y agoJust use Ohm's Law: V=IR (voltage = current x resistance).
Wiki User
∙ 11y ago27
Add your answer:
Earn +20 pts
How much power will be dissipated by resistor R4?
Facts missing. Need two of three values. The resistors value. The voltage across it. The current flowing through it. P=I^2*R. P=E^2/R
What process will double the power dissipated by a resistor?
Increase the voltage across the resistor by 41.4% .
At what level will typical resistors burn out?
A typical resistor will burn out when it dissipates power in excess of double its power dissipation rating for an extended period of time. The power dissipated by a resistor is equal to I2R or E2/R, where E = the voltage across the resistor I = the current through the resistor R = the resistance of the resistor
What is the voltage drop running through resistor 1 resistor 1 equals 3 ohms?
There is insufficient information in the question to answer it. You need to provide either the voltage across the resistor, or the power dissipated by the resistor. please restate the question.
What is the current running through a resistor of 9 ohms with volts of 90?
I = E / RIf the voltage across the resistor is 90 volts, and the resistance of the resistoris 9 ohms, then the current through the resistor is90/9 = 10 Amperes.Don't try this at home!The power dissipated by the resistor is E2/R = (90)2/9 = 900 watts. That's comparable to the power (heat) dissipated by a small toaster. A common composition resistor will get hot and possibly explode if it's asked to dissipate that kind of power.
2 resistors unequal value are in parallel. Would the power dissipated by the resistor with larger ohmic value be greater than the power dissipated by the resistor of lesser value?
No, because the power dissipated in a resistor is proportional to the square of the current through the resistor but only directly proportional to the resistance of the resistor (I^2 * R) and the current through the lower value resistor will be higher than the current through the higher value resistor, the lower value resistor will usually dissipate more power.
What power is dissipated by an 8.2 k resistor if a current of 0.005 amps pass's through the resistor?
.205 watts or 205 mw
A series circuit has 100mA flowing through a 1.5kohm load What is the power dissipated by the load?
A series circuit has 100mA flowing through a 1.5kohm load. The power dissipated by the load is equivalent to 15 Watt. This is based on the formula, power is equals to square current times load.
What process will double the power dissipated by a resistor?
Increase the voltage across the resistor by 41.4% .
How much power will be dissipated by resistor R4?
Facts missing. Need two of three values. The resistors value. The voltage across it. The current flowing through it. P=I^2*R. P=E^2/R
At what level will typical resistors burn out?
A typical resistor will burn out when it dissipates power in excess of double its power dissipation rating for an extended period of time. The power dissipated by a resistor is equal to I2R or E2/R, where E = the voltage across the resistor I = the current through the resistor R = the resistance of the resistor
What is the voltage drop running through resistor 1 resistor 1 equals 3 ohms?
There is insufficient information in the question to answer it. You need to provide either the voltage across the resistor, or the power dissipated by the resistor. please restate the question.
What is the current running through a resistor of 9 ohms with volts of 90?
I = E / RIf the voltage across the resistor is 90 volts, and the resistance of the resistoris 9 ohms, then the current through the resistor is90/9 = 10 Amperes.Don't try this at home!The power dissipated by the resistor is E2/R = (90)2/9 = 900 watts. That's comparable to the power (heat) dissipated by a small toaster. A common composition resistor will get hot and possibly explode if it's asked to dissipate that kind of power.
Ac power that is converted to heat in a resistor is known as?
real power (as opposed to imaginary power, which is not dissipated)
How Determine the power dissipated by the resistor?
Power dissipated by the resistor = I^2 * R or V^2 / R, where R = its resistance value, I = the current in the resistor, and V = the voltage drop across the two terminals of the resistor. You need to measure or find the information of either I (using an ammeter) or V (a voltmeter).
What is the power dissipated by a resistor with a current of 2 amps and a resistance of 1000 ohms?
I = 2A R = 1000Ω Power Dissipated P = I2R = (2A)2(1000Ω) = 4000W Voltage across resistor V = IR = (2A)(1000Ω) = 2000V
Calculate the Power in watts dissipated by a resistor of 1000 ohms with 200 volts across it 2 watts 20 watts 40 watts 400 watts?
Ohms law states that V = I * R I = V/R R = V/I P = I*V Where V = Voltage, I=Current, R = Resistance and P = Power or Watt Watt is the amount of electricity flowing through a line which is (Voltage times Current in (Amperage) = Power or watts) To find the power dissipated by a resistor of 1000 ohms, we first find the current I. The voltage is given as 200volts. Therefore I = V/R = 200/1000 = 0.2Amps We said Power or Watt = I*V Therefore the Power or watts dissipated by a resistor of 1000 ohms will be P=I*V = 200*0.2 = 40 Watts
