According to ohm's law V = IR.
So here
I=V/R
=12/4
I=3A
V=i*r=2*6=12v
Voltage can be calculated using Ohm's Law:Voltage = Current (A) x Resistance (Ω)Voltage = 4A x 3Ω = 12 VoltsTherefore, the battery is a 12 Volts.The power dissipated is Voltage x CurrentPower = 4A x 12V = 48 Watts
That would also depend on battery chemistry.
011.1
To calculate the current you need to take theWatt rating of your welder and divide this by the voltage youhave setthe machine at- this gives the amperage. So for a 1440 watt welder running at 12v the current would be: 1440 watt/ 12v = 120 Amps
V=i*r=2*6=12v
Resistance = voltage / current = 12V / 2.5mA = 12V / (2.5 x 10-3 A) = 4.8 x 103 ohm
According to ohms law (R=V/I) if voltage increases the resistance also increases .For example: If voltage (V) becomes 2 times the resistance (R) also increases becomes 2 times keeping the current (I) same
Wattage or power rating of a product can be calculated by multiplying voltage rating and current rating. (Power = Voltage x Current). e.g. if device is working at 12V and 2A is the current rating. It is 24Watt. Since Voltage = Current x Resistance , for a resistive load power can also be calculated by Power = Current x Current x Resistance = I^2 x R = I square R
The power dissipated by a circuit with a voltage of 12V and a current of 3A is 36W. Watts is Volts times Amps.
The output voltage of 12V 5W solar panel is 12V. The current is 0,41667A. These values are normaly calculated with 1000W/m2 of solar radiation.
Assume the supply as DC (Only resistance given) Voltage drop = 10X10X0.12 = 12V (approx)
Yes, you need to match the Voltage, the current (A) need to be the same or higher.
Its normal. There's two components to electrical power: voltage and current. A voltage is merely a "potential" to do electrical work. The amount of resistance in a circuit with respect to the amount of potential is what determines how much current flows. Its simple ohms law: Voltage = Current * Resistance, Power = Voltage * Current. Pulling the fuses out of the fuse box leaves an open circuit, which is an infinite amount of resistance. So by pulling your fuses, you prevent current from flowing, but you haven't taken away your battery's potential to do work (its voltage.) The voltage is always there as long as the battery is charged, but no current will flow or power be realized unless you reduce that resistance to something less than infinite by connecting a circuit to it (or in this case, completing the circuit again by replacing the fuses.)
Resistor values are given in ohms. A value may be selected to deliver a specific current at a given voltage. This is given in what is known as Ohm's Law where: Voltage (V) = Current (A) X Resistance (Ohm) A 12ohm resistor placed across a 12V battery would pass 1Amp of current and put out 12W of heat.
Voltage can be calculated using Ohm's Law:Voltage = Current (A) x Resistance (Ω)Voltage = 4A x 3Ω = 12 VoltsTherefore, the battery is a 12 Volts.The power dissipated is Voltage x CurrentPower = 4A x 12V = 48 Watts
Resistor values are given in ohms. A value may be selected to deliver a specific current at a given voltage. This is given in what is known as Ohm's Law where: Voltage (V) = Current (A) X Resistance (Ohm) A 12ohm resistor placed across a 12V battery would pass 1Amp of current and put out 12W of heat.