You must be thinking of the classical precipitation reaction done in many freshmen chemistry science labs, the mixture of lead nitrate and potassium iodide:
* Pb(NO3)2(s) + 2 KI(s) → PbI2(s) + 2 KNO3(s) The precipitate, lead (II) iodide (PbI2) is a toxic, yellowish solid. Lead iodide is toxic due to its lead content. It displays a range of colors with varying temperature from bright yellow at room temperature to brick red. On cooling, its color returns to yellow. Currently, it only finds use in its crystalline form, where it is used as a detector material for high energy photons including x-rays and gamma rays. In the nineteenth century it was used as an artists' pigment under the name Iodine Yellow, but it was too unstable to be useful.
potassium nitrate (aq) and lead iodide (s) are formed to create a yellow cloudy substance in a yellow liquid that will settle as a powder.
A yellow Lead(II) iodide precipitate
Pour a solution of Sodium(or Potassium) Iodide over Lead nitrate solution. The Lead iodide will be precipitated out as a yellow solid
This is a double displacement reaction. 2KI + Pb(NO3)2 --> 2KNO3 + PbI2 Potassium iodide + Lead(II) nitrate --> Potassium nitrate + Lead(II) iodide A bright yellow precipitate will form when these two react.
The reaction of potassium iodide (KI) and lead nitrate, Pb(NO3)2 is a double displacement reaction. It looks like this: 2KI(aq) + Pb(NO3)2(aq) ==> PbI2(s) + 2KNO3(aq). Note that PbI2 is a solid, and it happens to have a yellow color.
potassium nitrate (aq) and lead iodide (s) are formed to create a yellow cloudy substance in a yellow liquid that will settle as a powder.
A yellow Lead(II) iodide precipitate
Pour a solution of Sodium(or Potassium) Iodide over Lead nitrate solution. The Lead iodide will be precipitated out as a yellow solid
A yellow precipitate of silver iodide (AgI).
This is a double displacement reaction. 2KI + Pb(NO3)2 --> 2KNO3 + PbI2 Potassium iodide + Lead(II) nitrate --> Potassium nitrate + Lead(II) iodide A bright yellow precipitate will form when these two react.
Lead iodide (Pb2I) precipitates as a yellow solid, leaving a solution of potassium and nitrate ions.
Yellow; the insoluble precipitate Lead(II) iodide is created
A yellow precipitate of silver iodiode (AgI) is formed.
Pb(NO3)2 + 2NaI = PbI2 = 2NaNO3 Lead iodide is a yellow precipitate.
The reaction of potassium iodide (KI) and lead nitrate, Pb(NO3)2 is a double displacement reaction. It looks like this: 2KI(aq) + Pb(NO3)2(aq) ==> PbI2(s) + 2KNO3(aq). Note that PbI2 is a solid, and it happens to have a yellow color.
Produces yellow Lead(II) iodide and Sodium nitrate
A precipitate of yellow Lead iodide and Sodium nitrate are formed