Charge the capacitor.
Potential difference is a scientific term for what is more commonly called voltage.
ANSWER: If big enough the battery will see a short initially and then proceed to charge the capacitor at a rate of 63% of the voltage in one time constant defined as RC For engineering purposes after 5 time the time constant the battery will and the capacitor zero potential different. The proper term should be virtual no difference.
The units of capacitance are called farads. A one farad capacitor is a capacitor with 1 volt potential difference with 1 coulomb of charge on the capacitor, C = Q/V or Q=CV So the charge held on your capacitor is Q = CV = 9Volts * 0.40*10-6Farads=3.6*10-6 Coulombs
the plates of capacitor are connected to the same battery so same potential difference will develop across the plates of capacitors, as a result charges of same magnitude will be stored, as the charges are being supplied by the same battery.
A capacitor that is suddenly connected to a battery will charge to the battery voltage. The time to do this is dependent on the current capacity of the battery and wiring, and the capacitance of the capacitor. This represents an instantaneous short circuit, which lasts for a (usually) very short time - but damage could be done if there was no resistance. A charged capacitor that is suddenly disconnected from a battery will hold that voltage. The length of time it will hold is dependent on how much leakage current there is.
6 volts
The potential difference across two resistors connected in parallel to a battery with a potential difference of 6 volts is 6 volts. Kirchoff's Voltage Law: The signed sum of the voltage drops in a series circuit is zero. This means that that the two series circuits involving the battery and each resistor have the same voltage across each other, and the series circuit involving the two resistors have the same voltage across each other.
The units of capacitance are called farads. A one farad capacitor is a capacitor with 1 volt potential difference with 1 coulomb of charge on the capacitor, C = Q/V or Q=CV So the charge held on your capacitor is Q = CV = 9Volts * 0.40*10-6Farads=3.6*10-6 Coulombs
the plates of capacitor are connected to the same battery so same potential difference will develop across the plates of capacitors, as a result charges of same magnitude will be stored, as the charges are being supplied by the same battery.
A Battery or a capacitor.
If the capacitor isn't punctured or failed, then it becomes charged to the voltage of the battery almost immediately after it's connected to it, and stays that way.
A terminal potential difference is the potential difference appearing across the terminals of a voltage source, such as a battery or a generator, which varies according to the load supplied.When the battery or generator is off load (i.e. no load is connected to it), the terminal potential difference is equal to the electromotive force of that battery or generator.The terminal potential difference tends to decrease as the load current increases, due to a corresponding increase in the internal voltage drop of the battery or generator.
A capacitor that is suddenly connected to a battery will charge to the battery voltage. The time to do this is dependent on the current capacity of the battery and wiring, and the capacitance of the capacitor. This represents an instantaneous short circuit, which lasts for a (usually) very short time - but damage could be done if there was no resistance. A charged capacitor that is suddenly disconnected from a battery will hold that voltage. The length of time it will hold is dependent on how much leakage current there is.
Whichever plate is connected to the positive end of a battery.
The capacitor will hold the charge, until it leaks off due to resistances in the dielectric or external.
the charge on the capacitor had increased.
To measure the total emf simply connect the battery and voltmeter with the right terminals , but to measure the terminal potential difference which is less than the emf the voltmeter is connected in parallel with the battery
For a long time, The capacitor will be charged to the voltage of the DC battery, the positive side of the capacitor touching the positive terminal of the battery. Not much DC current will conduct, except for some tiny leakage current due to imperfection of the cap. The battery will be drained eventually.
A battery stores chemical energy creating a voltage or potential difference that is the potential to do work.When a battery is connected to an electrical device, current flow and is so the conversion of chemical energy into electrical energy.