No. It means it has a resistance of 2,200,000 Ohms. Plus or minus the tolerance.
A 100 ohm resistor carrying a current of 0.3 amperes would, by Ohm's Law, have a potential difference of 30 volts. A current of 0.3 amperes through a voltage of 30 volts would, by the Power Law, dissipate a power of 9 watts. You need a 10 watt resistor, alhough it is better to use a 20 watt resistor. E = IR 30 = (0.3)(100) P = IE 9 = (30)(0.3)
Resistor is an eletrical and electronical part whose function is to decrease the value of the voltage in a circuit, consequently reducing the value of the current, which is measured in Amperes.
Electrical current is measured in amperes.
To measure the value of a resistor, apply a voltage and measure the voltage across the resistor and the current through the resistor. Use Ohm's law: Resistance equals Voltage divided by Current. Start with a small voltage and increase gradually until a reading is obtained, but be careful that the power dissipation (watts = volts times amperes) of the resistor is not exceeded. Simpler solution: Use an ohmeter.
Ohm's law: current equals voltage divided by resistance, so a 203 ohm resistor would draw 0.57 amperes from a 115 volt power supply.
if you want to find the current (in amperes) through the resistor then connect a ammeter in series with the resistor.
The power in a resistor (in watts) is simply the product of the current (in amperes) times the voltage (in volts).The power in a resistor (in watts) is simply the product of the current (in amperes) times the voltage (in volts).The power in a resistor (in watts) is simply the product of the current (in amperes) times the voltage (in volts).The power in a resistor (in watts) is simply the product of the current (in amperes) times the voltage (in volts).
2 A (amperes)
If a 9.0 volt battery is connected to a 4.0-ohm and 5.0-ohm resistor connected in series, the current in the circuit is 1.0 amperes. If a 9.0 volt battery is connected to a 4.0-ohm and 5.0-ohm resistor connected in parallel, the current in the circuit is 0.5 amperes.
A 100 ohm resistor carrying a current of 0.3 amperes would, by Ohm's Law, have a potential difference of 30 volts. A current of 0.3 amperes through a voltage of 30 volts would, by the Power Law, dissipate a power of 9 watts. You need a 10 watt resistor, alhough it is better to use a 20 watt resistor. E = IR 30 = (0.3)(100) P = IE 9 = (30)(0.3)
Ohm's Law: Voltage is current times resistance.0.20 amperes times 3090 ohms is 618 volts.WARNING: This is also 124 watts, so do not attempt to duplicate this in the lab unless you have the appropriate equipment. In particular, an "ordinary" half-watt resistor will self destruct, causing a fire, if you try this.
If there's nothing else between the ends of the resistor and the power supply, then the voltage across the resistor is 24 volts, and the current through it is 2 amperes.
The current I = 0.18257 amperes. Scroll down to related links and look at "Electrical voltage V, amperage I, resistivity R, impedance Z, wattage P".
The current depends on the total effecvtive resistance of everything connectedacross the battery.If the resistor is the only component there, then the current is E/R = 12/3 = 4 amperes.
The question does not make sense. Ohms is a unit of resistance, while amperes is a unit of current. The two are not related unless a third item is given, such as volts. Please restate the question.
If the 3-ohm resistor is the ONLY thing in the circuit, then the current flowing through it is (12 volts)/(3 ohms) = 4 amperes. If there are other things in the circuit besides the resistor, then the current depends on all of them.
If they're in parallel, then each resistor acts as if it were the only one,and the presence of any others is irrelevant.The current through the 60-ohm resistor is I = E/R = (120/60) = 2 amperes.