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The molecule O=O is an O2 molecule. Oxygen is a diatomic compound, which means, that in nature, you will find oxygen only in the following form - O2, and not as O alone.

The answer to your question is - 1 sigma bond and 1 pie bond.

The bond formed between the two atoms is a covalent bond:

The covalent bond is essentially formed by a balance of electrostatic repulsion and attraction forces - while the two nucleuses and the electrons of each atom repulse each other, the nucleuses each attract electrons. If the atoms are close enough to one another, they will form a covalent bond, sharing electron pairs. When the covalent bond is formed, the incomplete orbitals of each atom combine. For example - in the case, each hydrogen atom has a 1s orbital with only one electron, and strives to complete that orbital with a second electron. When the two hydrogen atoms bond, they share a 1s orbital, containing both electrons, the bond is called a sigma bond. This theory is known as the molecular orbital theory.

When two atoms bond, they can share more than one electron pair, for example, in the case of , in which each oxygen atom "donates" two electrons to the covalent bond, filling the 2p orbital of both. This is called a double bond, containing one sigma bond and one pie bond. The sigma bond is stronger, and less likely to break. However, the pie bond compresses the bond and makes the two atoms closer to one another. A triple bond is also possible.

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13y ago
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1w ago

There is 1 sigma bond and 2 pi bonds present in the molecule 0=0 (oxygen molecule). Each oxygen atom forms a sigma bond with the other oxygen atom, and there are two pi bonds that form between the two oxygen atoms.

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Q: Which combination of bonds is present in this molecule 0 equals 0 1 sigma bond only 1sigma bond andpi bond 2 pi bonds or 1 sigma bond and 2 pi bonds?
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