Sodium and bromine are the elements in sodium bromide (NaBr) compound.
NaBr are two different elements. they are sodium and bromine.
NaBr is Sodium Bromide (Na is Sodium, Br is Bromine) Usually when you link only two elements together the ending of the product is -ide
It is Sodium Bromide, which is a halide (group 7 elements), yes, it is a variation of salt in a compound.
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Get moles NaBr 1.5 M NaBr = moles NaBr/0.075 Liters = 0.1125 moles NaBr (102.89 grams/1 mole NaBr) = 11.575 grams NaBr ( call it 12 grams ) ----------------------------------------------------
A formula unit of NaBr contains 2 atoms: 1 sodium and 1 bromine.
No, NaBr is a neutral salt.
There are two elements that make up the compound NaBr, or sodium bromide. These two elements are sodium and bromine.
NaBr is Sodium Bromide (Na is Sodium, Br is Bromine) Usually when you link only two elements together the ending of the product is -ide
It is Sodium Bromide, which is a halide (group 7 elements), yes, it is a variation of salt in a compound.
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Get moles NaBr 1.5 M NaBr = moles NaBr/0.075 Liters = 0.1125 moles NaBr (102.89 grams/1 mole NaBr) = 11.575 grams NaBr ( call it 12 grams ) ----------------------------------------------------
A formula unit of NaBr contains 2 atoms: 1 sodium and 1 bromine.
No, NaBr is a neutral salt.
NaBr is a salt.
Following the definitiion of molarity, 1.90 M = (weight in g) / (102.894 * 0.105) So weight of NaBr = 1.90 * 102.894 * 0.105 = 20.53 g
The reactions of Group 1 elements with Br2 are very vigorous. For example, Sodium it would go 2Na + Br2 = 2 NaBr.
The melting point of NaBr is 747 oC.
Sodium bromide (NaBr) is a salt.
2 Na + Br2 --> 2 NaBr