0
It's kind of hard to make copper sulphate without any sulphate being present.
Wiki User
∙ 13y ago
Add your answer:
Earn +20 pts
What you add firstly in carbohydrate solution either H2SO4 or 1-naphthol?
what is the intermediate after adding H2SO4 on naphthol?
What color will the solution be if you add H2SO4 to the K2CrO4 solution?
K2Cr2O7 + 6 KI + 7 H2So4 = Cr2(So4)3 + 4 K2So4 + 3 I2 + 7 H2O
How do you prepare 2N H2SO4 and 2M H2SO4?
MW of H2SO4 is 98.08. 2M = 2 x 98.08 in 1 L of water (1 gram=1 ml). Take 500 ml water in a 1 L measuring cylinder. Add 196.16 ml slowly along the side into water in the measuring cylinder. Use 50 ml pipette with automated pipettor. If needed you may want to keep the cylinder in ice to take care of the heat generated. Then make up to volume to 1 L with water. Eq. wt for H2SO4 = 98.08/2 = 49.039. SO for 2N solution, 2 eq.wt in 1 L. 98.08 ml in 1 L water adopting the method cited above.
How do you prepare an aqueous 3.0 M solution H2SO4 from crystal H2SO4?
Start with 1 dm^3 (1 Liter) of pure H2O. Molarity is defined as Mol/dm^3, so this is generally an easy way to go. Measure out 3 mol of H2SO4 -> First find the molar weight of Sulfuric acid, which is, according to Google: 98.079g/mol. So 3 mol * 98.079g/mol = 294.24 grams of H2SO4. Add that to 1 Liter of water, and you'll have an aqueous 3 Molar solution!
How do you prepare the 1.25 percent H2SO4 solution?
Concentrated H2SO4 is 96 %.( In laboratory ) As density of concentrated H2SO4 is 1.84gm/ml we will need this number as well, and as the atomic mass of H2SO4 is 98.08,as it is dibasic for normality it is 49 hence, Calculation=((96/100)(1000)(1.84))/49=36.04 If H2SO4 concentrated is 36.04 M then for make a 1L solution of 1M H2SO4 (36.04)X (x) = 1X(1) x = 1 X(1) / (36.04) x=0.0277gm/ml of water x = 27.7 mL of 36M H2SO4 per liter Hence for 1N H2SO4 dissolve 27.7ml of it to 1000ml of solvent(Water) that means for 0.1 N H2SO4 2.77 ml of it to 1000mL of solvent.
What you add firstly in carbohydrate solution either H2SO4 or 1-naphthol?
what is the intermediate after adding H2SO4 on naphthol?
Why we add conc sulphuric acid in mohr salt in the titration of mohr salt against potassium dichromate?
For preparation of standard solution of Mohr salt {FeSO4.(NH4)2SO4.6H2O}, it's necessary to add dilute H2SO4 to prevent the Fe2+ ions of Mohr salt solution from undergoing oxidation (to Fe3+).
How do you make the salt copper sulphate from copper carbonate and sulphuric acid?
CuCO3 + H2SO4 --> CuSO4 + CO2 + H2O As this reaction shows just add copper carbonate crystals to a solution of sulfuric acid of diluted concentration. Carbon dioxide should efferves from this solution. I can not remember if the copper sulfate precipitates here, or is in ionized form.
What color will the solution be if you add H2SO4 to the K2CrO4 solution?
K2Cr2O7 + 6 KI + 7 H2So4 = Cr2(So4)3 + 4 K2So4 + 3 I2 + 7 H2O
Is there an ion exchange when you add CuSO4 to NaCl?
The Cu2+ from CuSO4 is displaced by the Na+ from NaCl and CuCl2 and Na2SO4 are formed.
How do you prepare 2N H2SO4 and 2M H2SO4?
MW of H2SO4 is 98.08. 2M = 2 x 98.08 in 1 L of water (1 gram=1 ml). Take 500 ml water in a 1 L measuring cylinder. Add 196.16 ml slowly along the side into water in the measuring cylinder. Use 50 ml pipette with automated pipettor. If needed you may want to keep the cylinder in ice to take care of the heat generated. Then make up to volume to 1 L with water. Eq. wt for H2SO4 = 98.08/2 = 49.039. SO for 2N solution, 2 eq.wt in 1 L. 98.08 ml in 1 L water adopting the method cited above.
How do you prepare an aqueous 3.0 M solution H2SO4 from crystal H2SO4?
Start with 1 dm^3 (1 Liter) of pure H2O. Molarity is defined as Mol/dm^3, so this is generally an easy way to go. Measure out 3 mol of H2SO4 -> First find the molar weight of Sulfuric acid, which is, according to Google: 98.079g/mol. So 3 mol * 98.079g/mol = 294.24 grams of H2SO4. Add that to 1 Liter of water, and you'll have an aqueous 3 Molar solution!
What compounds make a buffer solution with a pH of 7 neutral?
For the preparation of a solution with the pH=7,00:Add 29,1 mL sodium hydroxide solution 0,1 M to 50 mL potassium dihydrogen phosphate solution 0,1 M.
How do you prepare the 1.25 percent H2SO4 solution?
Concentrated H2SO4 is 96 %.( In laboratory ) As density of concentrated H2SO4 is 1.84gm/ml we will need this number as well, and as the atomic mass of H2SO4 is 98.08,as it is dibasic for normality it is 49 hence, Calculation=((96/100)(1000)(1.84))/49=36.04 If H2SO4 concentrated is 36.04 M then for make a 1L solution of 1M H2SO4 (36.04)X (x) = 1X(1) x = 1 X(1) / (36.04) x=0.0277gm/ml of water x = 27.7 mL of 36M H2SO4 per liter Hence for 1N H2SO4 dissolve 27.7ml of it to 1000ml of solvent(Water) that means for 0.1 N H2SO4 2.77 ml of it to 1000mL of solvent.
What are two ways to make a solution more acidic?
Since acidity is a concentration of H+ ions, we can simply add them (in the form of an acid, such as HCl or H2SO4) or we can remove OH-. The easiest way to remove OH is to just add H, however.
If you have 2 liters of 2 M NaCl you take 500 ml of that and add it to 500ml of pure water the new 1000 ml preparation is now?
A solution of NaCl 1 M.
What is foulger's reagent?
40g urea+ 80ml of 40%H2SO4! add 2g stannous chloride, heat untill solution is clear and make the volume upto 100ml. it is called foulger's reagent!
