I think it is to determine how powerful you have to make your power supply to run the current demand load continously with a margin for error on the plus side. A 12 volt car battery has a low load resistance and needs some heafty components in a battery charger. A charger (or supply) for a 12 volt boom box with a high load resistance may be the size of a small paper cup. They both supply 12-15 volts but the load resistance is very much different E=IR I=E/r R=E/i
because across load resistance only we can messure current
Do not add any unwanted device in the circuit. Have correct sized wire for the application and the load current.
Do not add any unwanted device in the circuit. Have correct sized wire for the application and the load current.
To solve any D.C. circuit by using Thevenin Theorem,First of all load resistance RL is disconnected from the circuit and open circuit voltage across the circuit is calculated (known as Thevenin equivalent voltage)Secondly, the battery is removed by leaving behind its internal resistance. Now we calculate equivqlent resistance of the circuit ( called Thevenin equivalent resistance).Now we connect Thevenin Voltage in series with Equivalent resistance of the circuit and now connect load resistance across this circuit to calculate current flowing through the load resistance.Whereas in the case of using Norton theorem, we again remove the load resistance if any, and then short circuit these open terminals and calculate short circuit current Isc.Second step is same as in Thevenin theorem i.e. remove all sources of emf by replacing their internal resistances and calculate equivqalent resistance of the circuit.Lastly, join short circuit current source in parallel with equivalent resistance of the circuit. Now, we can calculate votage across the resistance which was connected in parallel with Isc.So, by knowing the open circuit voltage, we can calculate current flowing the resistance and on the other hand , by knowing the short curcuit current , we can calculate voltage across the resistance.
As load is conected in circuit , so thre is no open circuit therefore there would not be any open circuit voltage.
lowest resistance
Any specific device that draws a current which is connected within the circuit is an example of a circuit load. That may be a resistance and a loudspeaker LED computer and induction motor or whatever which can withdraw the energy from the output.
Do not add any unwanted device in the circuit. Have correct sized wire for the application and the load current.
Do not add any unwanted device in the circuit. Have correct sized wire for the application and the load current.
No. No load and short circuit is not similar. No load can be 1) Either open circuit i.e. Only Potential is available and load is not connected 2) Load (i.e. motor etc ) is connected but not working with full load or full capacity. In this case the current will flow through the circuit depending on the load. It means No load condition is a condition where no current or a small ( relative / comparative term) current is flowing through the circuit. In Short circuit the load side resistance/ impedance become so less that very high amount of current is passing through circuit.( The protection is therefor required for any circuit) No load and and short circuit is not similar. Thanks
To solve any D.C. circuit by using Thevenin Theorem,First of all load resistance RL is disconnected from the circuit and open circuit voltage across the circuit is calculated (known as Thevenin equivalent voltage)Secondly, the battery is removed by leaving behind its internal resistance. Now we calculate equivqlent resistance of the circuit ( called Thevenin equivalent resistance).Now we connect Thevenin Voltage in series with Equivalent resistance of the circuit and now connect load resistance across this circuit to calculate current flowing through the load resistance.Whereas in the case of using Norton theorem, we again remove the load resistance if any, and then short circuit these open terminals and calculate short circuit current Isc.Second step is same as in Thevenin theorem i.e. remove all sources of emf by replacing their internal resistances and calculate equivqalent resistance of the circuit.Lastly, join short circuit current source in parallel with equivalent resistance of the circuit. Now, we can calculate votage across the resistance which was connected in parallel with Isc.So, by knowing the open circuit voltage, we can calculate current flowing the resistance and on the other hand , by knowing the short curcuit current , we can calculate voltage across the resistance.
Not sure what you mean. The equivalent (total) resistance in a parallel circuit is less than any individual resistance.
In electronics , a circuit is a complate circular path that electricity flows through.A simple circuit consists of a current source .conductor and a load . The term circuit can be used in a general sence to refer to any fixed path that electrocity,data or a signal can travel through.
In electronics, a circuit is a complete circular path that electricity flows through. A simple circuit consists of a current source, conductors and a load. The term circuit can be used in a general sense to refer to any fixed path that electricity, data or a signal can travel through.
A: practically any series resistance will do that
As load is conected in circuit , so thre is no open circuit therefore there would not be any open circuit voltage.
It is load resistance RL. It can be any device that can act as a load at the output end. Example : A resistor
A open circut is a not full rotation like a open circle Answer: It is circuit that has no load connected to it. Therefore it may BE ABLE drive any circuit if if there a load but without a load it is open circuit. Here is an example of an open circuit: a "blown" fuse in a power supply line. Current cannot flow through an open circuit.