Write a c program to compare two strings without using builtin function?

Answer 1

A string is a character array, so you can compare them one character at a time:

String x = "test"

String y = "test"

for(int i = 0; i < x.length && i < y.length; i++)

{

if(x[i] != y[i])

return false;

}

return true;

Answer 2

char one [] = "first string" ;
char two [] = "second string" ;

if (strcmp (one, two) == 0)
{
puts ("The strings are the same") ;
}
else if (strcmp (one, two) < 0)
{
puts ("String one is less than string two") ;
}
else
{
puts ("String one is greater than string two") ;
}

Answer 3

#include<stdio.h> int str_cmp(const char *s1, const char *s2) { unsigned int i = 0, diff; while(*(s1+i) && *(s2+i)) { diff = (*(s1+i)-*(s2+i)); if(!diff)i++; else break; } return diff; } int main() { printf("chuma %d ", str_cmp("abcd","abcde")); return 0; } U can use this as a prototype and enhance this. I havent even tried compilng this. Sujith

Answer 4

There are several comparison functions in C. If you read that section in your C library reference you will have no problems. The question is intended to make you study and understand comparison functions.

Answer 5

Make use of the fact that strings are null terminated character arrays in c and that the array variable is a reference to the starting address of the string.

#include

int stringComp( char str1[], char str2[]){

while( *str1 && *str2){//check for termination of any of the strings

if( *str1 < *str2)

return -1;

else if( *str1 > *str2)

return 1;

str1++;

str2++;

}

if( !(*str1) && !(*str2))//both the strings have terminated - checking for difference in length

return 0;

else if( !(*str1))//only str1 has terminated

return -1;

return 1;//only str2 has terminated

}

int main(){

char str1[20], str2[20];

int equal;

printf("Enter the two strings:\t");

scanf("%s%s", str1, str2);

equal = stringComp(str1, str2);

if( !equal)

printf("The two strings are equal\n");

else if( equal == -1)

printf("str1 is lesser than str2\n");

else

printf("str1 is greater than str2\n");

return 0;

}

Answer 6

The stricmp() function in C language compares two strings with case insensitivity. Java provides equalsIgnoreCase() method in Strings class for the same function.

void stringTest() {

String s1 = "foo";

String s2 = "Foo";

if (s1.equalsIgnoreCase(s1, s2))

System.out.println("strings equal");

else

System.out.println("strings not equal");

}

Output for this method would be:

> strings equal

Answer 7

using built in function

Answer 8

Use functions strlen and memcpy.