The amount of 1 mole: 6.022 * 1023 (Avogadro's constant)
At STP, 1 mole of any ideal gas occupies 22.4 liters. Therefore, 5 liters of NO2 at STP will represent 0.22 moles (5/22.4), and this is the case for any other ideal gas. So, the answer is that 5 liter of ANY ideal gas will have the same number of molecules as 5 liters of NO2.
There are 1 mole of nitrogen gas molecules contain 2 nitrogen atoms. Therefore, 0.25 mole of nitrogen gas would contain 0.25 * 2 = 0.5 moles of nitrogen atoms.
There are 6.02 x 10^23 molecules in one mole of a substance (Avogadro's number). At STP, 22.4 liters of any ideal gas contains 1 mole of gas. Therefore, there are 6.02 x 10^23 butane molecules in 22.4 liters of C4H10 gas at STP.
The product of N plus O2 to form NO2 is a chemical reaction where nitrogen and oxygen gas combine to form nitrogen dioxide gas. This reaction occurs when nitrogen and oxygen molecules react under specific conditions to produce the NO2 molecule.
The mole fraction of oxygen gas in air is approximately 0.21. This means that out of every 1 mole of air, 0.21 moles are oxygen gas molecules.
In 1 mole of NO2 gas, there are a total of 9 moles of protons. This is because NO2 has 1 nitrogen atom and 2 oxygen atoms, which contain a total of 9 protons (7 protons from nitrogen and 2 protons from each oxygen).
At STP, 1 mole of any ideal gas occupies 22.4 liters. Therefore, 5 liters of NO2 at STP will represent 0.22 moles (5/22.4), and this is the case for any other ideal gas. So, the answer is that 5 liter of ANY ideal gas will have the same number of molecules as 5 liters of NO2.
Since 1 mole is (6.022×1023 molecules)/(mol), so 9.02 x 1023 molecules would be 1.4978... mol
ABigNumber.
One mole is 6.02 × 1023 of anything.One mole of atoms is 6.02 × 1023 atoms, one mole of rice is 6.02 × 1023 grains, one mole of shoes is 6.02 × 1023 shoes. You get the picture?One mole of molecules is 6.02 × 1023molecules.
There are 3.01 x 10^23 atoms of sodium in 0.250 moles of Na2SO4. This is calculated by multiplying the Avogadro's number (6.022 x 10^23 atoms/mol) by the stoichiometric ratio (2 sodium atoms per molecule of Na2SO4).
This number is 6,022 140 857.
There are 1 mole of nitrogen gas molecules contain 2 nitrogen atoms. Therefore, 0.25 mole of nitrogen gas would contain 0.25 * 2 = 0.5 moles of nitrogen atoms.
There are 6.02 x 10^23 molecules in one mole of a substance (Avogadro's number). At STP, 22.4 liters of any ideal gas contains 1 mole of gas. Therefore, there are 6.02 x 10^23 butane molecules in 22.4 liters of C4H10 gas at STP.
The product of N plus O2 to form NO2 is a chemical reaction where nitrogen and oxygen gas combine to form nitrogen dioxide gas. This reaction occurs when nitrogen and oxygen molecules react under specific conditions to produce the NO2 molecule.
at stp 1 mole of a gas contains 22.4 litres. 9.1/22.4= .40625 moles o2. 1 mole of a gas contains 6.022E23 molecules so .40625 moles x 6.022E23 = 2.4464325E23 molecules, but you have to multiply by two due to it being diatomic, so answer x 2 = 4.892875E23 molecules
The mole fraction of oxygen gas in air is approximately 0.21. This means that out of every 1 mole of air, 0.21 moles are oxygen gas molecules.