By definition, one mole would be the same as the Atomic Mass. You take the number of moles and multiply it by the atomic mass. So if you have just 1 mole, the number of grams will be the atomic mass. Calcium's atomic mass is 40.08 grams.
(2.7 mol Ca / 1) * (40.078 g Ca / 1 mol Ca) = 108.21 g Ca. After significant figures, the answer is 110 g Ca.
To find the number of moles in 5000 grams of calcium, you need to divide the given mass by the molar mass of calcium. The molar mass of calcium is approximately 40.08 g/mol. So, 5000 grams of calcium is equal to 5000/40.08 = 124.69 moles of calcium.
To find the mass of calcium phosphate (Ca₃(PO₄)₂) in grams for 0.658 moles, first calculate its molar mass. The molar mass of calcium phosphate is approximately 310.18 g/mol. Multiply the number of moles by the molar mass: 0.658 moles × 310.18 g/mol ≈ 204.4 grams. Thus, there are about 204.4 grams of calcium phosphate in 0.658 moles.
2 moles of Ca and 4 moles of OH
To find the number of moles of calcium (Ca) in 40.1 grams, you can use the formula: moles = mass (g) / molar mass (g/mol). The molar mass of calcium is approximately 40.08 g/mol. Therefore, the calculation is 40.1 g / 40.08 g/mol, which is about 1.0005 moles of calcium.
3.8 grams calcium (1 mole Ca/40.08 grams) = 0.09 moles calcium ==============
For this you need the atomic mass of Ca. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. Ca= 40.1 grams.761 moles Ca × (40.1 grams) = 30.5 grams Ca
(2.7 mol Ca / 1) * (40.078 g Ca / 1 mol Ca) = 108.21 g Ca. After significant figures, the answer is 110 g Ca.
126 grams calcium (1 mole Ca/40.08 grams) = 3.14 moles of calcium ------------------------------
To calculate the amount of Ca(NO3)2 needed for a 0.50M solution: Find the molar mass of Ca(NO3)2 = 164.09 g/mol. Calculate the number of moles needed: 0.50 moles/L x 0.250 L = 0.125 moles. Convert moles to grams: 0.125 moles x 164.09 g/mol ≈ 20.51 grams of Ca(NO3)2 are needed.
For this you need the atomic mass of Ca. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.40.0 grams Ca / (40.08 grams) = .998 moles Ca
Molarity = moles of solute/Liters of solution ( 300.0 ml = 0.300 liters ) ( Ca(OH)2 is correct formulation ) 0.115 M Ca(OH)2 = moles Ca(OH)2/0.300 Liters = 0.0345 moles Ca(OH)2 (74.096 grams/1 mole Ca(OH)2) = 2.56 grams of Ca(OH)2 needed
Well, darling, the molar mass of calcium (Ca) is approximately 40.08 g/mol. So, if you have 3.61 moles of Ca, you just need to multiply the molar mass by the number of moles to find the mass. In this case, 3.61 moles of Ca would have a mass of around 144.88 grams. Hope that clears things up for you, sugar!
To determine the number of moles of calcium atoms in 98.5 g of Ca, you need to first calculate the molar mass of Ca (40.08 g/mol). Then, divide the given mass by the molar mass to get the number of moles. So, 98.5 g of Ca is equal to 98.5 g / 40.08 g/mol ≈ 2.46 moles of Ca atoms.
To find the number of moles in 5000 grams of calcium, you need to divide the given mass by the molar mass of calcium. The molar mass of calcium is approximately 40.08 g/mol. So, 5000 grams of calcium is equal to 5000/40.08 = 124.69 moles of calcium.
To find the number of moles, you need to divide the given mass of calcium by its molar mass. The molar mass of calcium (Ca) is approximately 40.08 g/mol. Number of moles = 77.4 g / 40.08 g/mol ≈ 1.93 moles.
To find the mass of calcium phosphate (Ca₃(PO₄)₂) in grams for 0.658 moles, first calculate its molar mass. The molar mass of calcium phosphate is approximately 310.18 g/mol. Multiply the number of moles by the molar mass: 0.658 moles × 310.18 g/mol ≈ 204.4 grams. Thus, there are about 204.4 grams of calcium phosphate in 0.658 moles.