0
What else can I help you with?
How many grams of oxygen gas can be formed from the decomposition of 0.437 mol HgO?
By using the balanced chemical equation for the decomposition of mercury(II) oxide (HgO): 2 HgO -> 2 Hg + O2, we see that 1 mol of HgO produces 1 mol of O2. Therefore, 0.437 mol of HgO will produce 0.437 mol of O2. To convert mol to grams, we use the molar mass of oxygen: 32.00 g/mol. so, 0.437 mol of O2 is equivalent to 0.437 mol * 32.00 g/mol = 13.92 grams of O2.
How many GRAMS of hydrogen are present in 2.08 moles of water?
In 1 mole of water (H2O), there are 2 moles of hydrogen (H). This means that in 2.08 moles of water, there are 2.08 x 2 = 4.16 moles of hydrogen. To convert moles to grams, we use the molar mass of hydrogen: 4.16 moles x 1.01 g/mol = 4.22 grams of hydrogen.
How many moles are in 2 grams of HCL?
To find the number of moles in 2 grams of HCl, you need to divide the mass by the molar mass of HCl. The molar mass of HCl is approximately 36.46 g/mol. Therefore, 2 grams of HCl is equal to 2/36.46 = 0.055 moles.
How many grams in 2 moles of sodium?
Mass of 2 moles of Na = 2 x atomic mass of Na = 2 x 23.0 = 46.0g
How many grams of hydrogen are needed to produce 30.0 grams of water?
The synthesis reaction is 2 H2 + O2 = 2 H2O. Every two moles of hydrogen reacts with one mole of oxygen to make two moles of water. Then 30.0 grams of water is 1.67 moles, and 1.67 moles of H2 has a mass of 3.37 grams. 25.0 grams of O2 is .781 moles, so 1.562 moles of H2 are needed, or 3.15 grams.
How many moles of mercury (II) oxide are needed to produce 125 g of oxygen?
To determine how many moles of mercury (II) oxide (HgO) are needed to produce 125 g of oxygen (O₂), we first need to consider the decomposition reaction: 2 HgO(s) → 2 Hg(l) + O₂(g). From this equation, we see that 2 moles of HgO produce 1 mole of O₂. The molar mass of O₂ is approximately 32 g/mol, so 125 g of O₂ corresponds to about 3.91 moles (125 g ÷ 32 g/mol). Therefore, since 2 moles of HgO produce 1 mole of O₂, we need 7.82 moles of HgO (3.91 moles O₂ × 2 moles HgO/mole O₂).
How many moles of mercury (II) oxide are needed to produce 125 grams of oxygen?
To find the moles of mercury (II) oxide (HgO) needed to produce 125 grams of oxygen (O2), we first calculate the moles of O2. The molar mass of O2 is approximately 32 g/mol, so 125 g of O2 corresponds to about 3.91 moles (125 g ÷ 32 g/mol). The decomposition of 2 moles of HgO produces 1 mole of O2, meaning we need 7.82 moles of HgO (3.91 moles O2 × 2) to produce that amount of oxygen. Thus, 7.82 moles of mercury (II) oxide are required.
What is the mass of 2 moles of water (H2O)?
A mole of HNO3 weighs 63g (1 + 14 +16x3). Therefore, two moles weigh, 2 x 63 =126 g
In the formula 2HgO the coefficient is?
The coefficient in front of the compound HgO in the formula 2HgO is 2. This means there are 2 moles of HgO for every 2 moles of the whole compound.
How many moles are in 56 grams of carbon monoxide?
moles = weight in grams / molecular weight = 56 / 28 = 2 moles
How many moles are in 987 grams of Ra(OH)2?
987 grams of Ra(OH)2 is equivalent to 3,78 moles.
How many moles in 987 grams of Ra(OH)2?
987 grams of Ra(OH)2 is equal to 3,78 moles.
How many moles are in 124.60 grams of Fe3(PO4)2?
124,60 grams of Fe3(PO4)2 are equal to 0,35 moles.
How many moles of oxygen gas O2 are in 64 grams of O2?
The answer is 2 moles.
How many moles of nitrogen are there in 29 grams of nitrogen?
There are 29/14, or just over 2 moles of nitrogen in 19 grams.
How many grams of oxygen gas can be formed from the decomposition of 0.437 mol HgO?
By using the balanced chemical equation for the decomposition of mercury(II) oxide (HgO): 2 HgO -> 2 Hg + O2, we see that 1 mol of HgO produces 1 mol of O2. Therefore, 0.437 mol of HgO will produce 0.437 mol of O2. To convert mol to grams, we use the molar mass of oxygen: 32.00 g/mol. so, 0.437 mol of O2 is equivalent to 0.437 mol * 32.00 g/mol = 13.92 grams of O2.
How many grams of oxygen will be in 2 moles of pottassium dichromate?
The answer is 224,141 grams oxygen.
