MgCl2 + 2KOH ==> Mg(OH)2 + 2KCl1 mole MgCl2 reacts with 2 moles KOH
2 moles KOH x 56.1 g/mole = 112.2 g KOH = 100 g KOH (to 1 significant figure based on 1 mole)
MgCl2 + 2KOH ==> Mg(OH)2 + 2KCl1 mole MgCl2 reacts with 2 moles KOH
2 moles KOH x 56.1 g/mole = 112.2 g KOH = 100 g KOH (to 1 significant figure based on 1 mole)
the answer is 2 apex ;)
The chemical reaction is:
MgCl2 + 2 KOH = Mg(OH)2 + 2 KCl
2 moles of KOH react with 1 mole of MgCl2.
(2)(56 g)
Assuming the reaction is 2KOH + MgCl2 --> 2KCl + Mg(OH)2, and you want both reactants to get used up completely, you must determine how may grams are in 2 moles of potassium hydroxide: KOH = 39+16+1= 56g * 2mol = 112 grams.
It's 1 for APEX. I just took the test and got it wrong.
(2)(56 g)
(2)(56 g)
apex : 2
2
From the balanced equation it can be seen that it takes 2 moles KOH to react with each 1 mole of MgCl2. So, the answer is 2.
The chemical reaction is:2 Mg + O2 = 2 MgO
Suppose we react 6.00 moles calcium with 4.00 mol oxygen gas. Determine the number of moles of oxygen left over after the reaction is complete.
First of all write down the BALANCED reaction equation. Mg(s) + 2HCl(aq) = MgCl2(aq) + H2(g) We note that the molar ratios are 1:2::1:1 Next calculate the moles of Mg mol(Mg) = 4.3 / 24.3 (Atomic mass) mol(Mg) = 0.17695... Hence by equivalence with the mole ratios 0.17695... moles of MgCl2 are produced. NB 1:2::1:1 becomes 0.17695 , 0.353909...:: 0.17695...:0.17695... 695... : 0.
2
From the balanced equation it can be seen that it takes 2 moles KOH to react with each 1 mole of MgCl2. So, the answer is 2.
1337
1
MgCl2 + 2KOH ==> Mg(OH)2 + 2KCl1 mole MgCl2 reacts with 2 moles KOH 2 moles KOH x 56.1 g/mole = 112.2 g KOH = 100 g KOH (to 1 significant figure based on 1 mole)
These compounds will not react. They both contain the same anion, and thus there can be no reaction between them. Consequently, the reactants will remain unchanged.
Potassium chloride and magnesium nitrate doesn't react.
1.5 moles of O2 react with 2 moles of Al 2Al + 1.5 O2 = Al2O3.
Al+HCl===> AlCl3+H2 Is the reaction. You need &.2 moles of HCl.
The chemical reaction is:2 Mg + O2 = 2 MgO
Suppose we react 6.00 moles calcium with 4.00 mol oxygen gas. Determine the number of moles of oxygen left over after the reaction is complete.
I assume you mean this reaction. Zn + 2HCl --> ZnCl2 + H2 2.3 moles zinc (2 moles HCl/1 mole Zn) = 4.6 moles hydrochloric acid needed ========================