Well, we would have to know how many % of the coding sequence would be exons and introns, but let's ignore this and assume 100% of the sequence are exons;
129 aminoacids = 129 codons = 129*3 nucleotides = 387 nucleotides.
10 pairs of bases = 3,4 nm;
387/10 = 38,7
38,7 * 3,4 = 131,58 nm.
Each orbital must contain a single electron before any orbital contains two electrons.
The Shine-Dalgarno sequence is prokaryotic. The Kozak sequence is the eukaryotic equivalent.
The sequence of codons in mRNA, or messenger RNA, is most directly responsible for the sequence of amino acids in a protein. Each codon is comprised of 3 nucleotides.
An amino acid sequence can be compared by using an electron microscope. The sequence of one acid can be viewed and then directly compared to another.
Verify given sequence in ap
The sequence needs to be complete or nothing will happen.
Equation
gene
379, but it does not complete the sequence which is infinite.
DNA sequences contain the nitrogen bases adenine, thymine, cytosine, and guanine. RNA sequences contain the nitrogen bases adenine, uracil, cytosine, and guanine. If the sequence contains thymine it is a DNA sequence if it contains uracil it is an RNA sequence.
27 BUT, as far as I can tell, it does not complete the sequence which can continue further.
His treatise, Liber abaci (1202), contains the famous Fibonacci sequence.
Sacramento, California.
genome
quadrillion
12436871416 is a single 11-digit number. A single number does not define a sequence.
Consider the sequence (a_i) where a_i is pi rounded to the i_th decimal place. This sequence clearly contains only rational numbers since every number in it has a finite decimal expansion. Furthermore this sequence is Cauchy since a_i and a_j can differ at most by 10^(-min(i,j)) or something which can be made arbitrarily small by choosing a lower bound for i and j. Now note that this sequence converges to pi in the reals, so it can not converge in the set of rational numbers. Therefore the rational numbers allow a non-convergent Cauchy sequence and are thus by definition not complete.