Well considering the average Atomic Mass of 1 mole of C = 12.01115g and the average atomic mass of 1 mole of O = 15.9994g you add 2*15.9994 and 12.01115 to get a mole to mass conversion of 44.00995g per mole of CO2. You then 4.73 moles apply it to the conversion. 4.73 moles * 44.00995g/mole = 208.1670635g, rounded for three significant figures to 208. g. The answer: 208g of CO2.
The MOLAR mass of carbon is 12.0 and the mass of carbon in this question is 3.43 grams. There is no MOLAR mass of 3.43 g of carbon. The question is meaningless.
3 moles CO2 x 44 g/mole CO2 = 132 g = 130 g (to 2 significant figures)
47.6 grams
2.3 g
For this you need the atomic (molecular) mass of CO2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. CO2=44.0 grams2.00 moles CO2 × (44.0 grams) = 88.0 grams CO2
to work out the number of moles, you divide the mass by the relative atomic mass so 200 divided by 44 = 4.55 moles
Atomic mass of C = 14g/mol Atomic mass of O = 16g/mol Molecular mass of CO2 = 12 + 2(16) = 44g/mol mass = number of moles x molecular mass mass = 3 mol x 44g/mol = 132g
First write the balance equation: Na2CO3 + 2HNO3 ==> 2NaNO3 + CO2 + H2O Next calculate moles of Na2CO3 used: 7.5 g x 1 mole/106 g = 0.071 moles Na2CO3 Then look at mole ratio of Na2CO3 to CO2 and see that it is 1 to 1 Thus, moles CO2 produced = 0.071 moles Finally, convert moles CO2 to grams of CO2: 0.071 moles x 44g/mole = 3.1 g (to 2 significant figures)
To determine the number of liters of carbon dioxide produced in this reaction, we need the balanced equation and the molar mass of carbon dioxide. The balanced equation is: CaCO3 + 2HCl → CaCl2 + CO2 + H2O The molar mass of CO2 is 44.01 g/mol. First, we calculate the number of moles of CaCO3: 906 g / molar mass of CaCO3 = moles of CaCO3 Using the balanced equation, we see that the stoichiometric coefficient of CO2 is 1. This means that the number of moles of CO2 produced is equal to the number of moles of CaCO3. Finally, we convert moles of CO2 to liters using the ideal gas law: moles of CO2 x 22.4 L/mol = liters of CO2. Therefore, the number of liters of CO2 produced from 906 grams of CaCO3 can be calculated as follows: liters of CO2 = (906 g / molar mass of CaCO3) x 22.4 L/mol
For this you need the atomic (molecular) mass of CO2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CO2=44.0 grams454 grams CO2 / (44.0 grams) = 10.3 moles CO2
5.0 grams CO2 (1mol CO2/44.01g) = 0.11 moles CO2
For this you need the atomic (molecular) mass of CO2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. CO2= 44.0 grams1.50 moles CO2 × (44.0 grams) = 66.0 grams CO2
For this you need the atomic (molecular) mass of CO2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. CO2=44.0 grams2.00 moles CO2 × (44.0 grams) = 88.0 grams CO2
1 mole CO2 has about 44 grams, so half a mole of CO2 equals 22 grams
just short of a mole. moles is mass/molar mass. mass is 42, molar mass is 44. 42/44
For this you need the atomic (molecular) mass of CO2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CO2=44.0 grams33.0 grams C / (44.0 grams) = .750 moles CO2
6.5 grams CO2 divided by 44 grams CO2 per mole CO2 = 6.8 mole CO2 (Molar mass CO2 = 12 + 2*16 = 44 g/mol)
Mass of 4 mole CO2 , this is 4 * (12 + 2*16) = 176 grams
C + O2 = CO2 So the theoretical number of moles are 1 each. number of moles is mass/molecular weight C = 6/12 which is 0.5 O2 = 11/32 which is 0.34375 Oxygen is the limiting reagent. So 0.34375 moles is reacted and this also gives 0.34375 moles CO2 no moles is mass over molecular mass grams is moles x molec mass 0.34375 x 44 = 15.125 grams CO2 formed. learn the technique. this is needed in science
look its easy. if you have X moles of Ca you would look it up in the elements chart and figure it out right? now all you have to do is figure out how many moles do you get of each element in the compound above and sum them up. if it still doesnt help post on my message bourd ok?
to work out the number of moles, you divide the mass by the relative atomic mass so 200 divided by 44 = 4.55 moles