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What is the molarity of a solution with 2 moles of NaOH in 1620ml of water?
The molarity of the solution can be calculated by dividing the moles of solute by the volume of solution in liters. In this case, 2 moles of NaOH in 1620 mL (1.62 L) of water gives a molarity of approximately 1.23 M.
How 0.1M NaOH form?
0.1 M NaOH is prepared by dissolving sodium hydroxide (NaOH) pellets or flakes in water to make a 0.1 molar solution. This means there are 0.1 moles of NaOH dissolved in 1 liter of water. The molarity of the solution is calculated using the formula: Molarity = moles of solute / liters of solution.
What is the molarity of a solution of 95 grams of NaOH to 450 ml of water?
To calculate the molarity, you first need to convert the grams of NaOH to moles using the molar mass of NaOH (40 g/mol). Then, you divide the moles of NaOH by the volume of solution in liters (450 ml = 0.45 L) to get the molarity. Molarity = moles of NaOH / volume of solution in liters Moles of NaOH = 95 g / 40 g/mol = 2.375 mol Molarity = 2.375 mol / 0.45 L = 5.28 M
What is the molarity of 4mol of NaOH dissolved in 2L of water?
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, the molarity of the solution with 4 mol of NaOH dissolved in 2 L of water would be 2 M.
What is the OH- in a solution that contains 0.240 g NaOH in 0.225 L of solution?
Molarity = moles solute/Liters solution get moles NaOH 0.240 grams NaOH (1 mole NaOH/39.998 grams) = 0.0060 moles NaOH ----------------------------------as one to one OH- has this many moles also Molarity = 0.0060 moles OH-/0.225 Liters = 0.0267 M OH- ----------------------- -log(0.0267 M OH-) = 14 - 1.573 = 12.4 pH -------------
What is the molarity of a solution with 2 moles of NaOH in 1620ml of water?
The molarity of the solution can be calculated by dividing the moles of solute by the volume of solution in liters. In this case, 2 moles of NaOH in 1620 mL (1.62 L) of water gives a molarity of approximately 1.23 M.
How 0.1M NaOH form?
0.1 M NaOH is prepared by dissolving sodium hydroxide (NaOH) pellets or flakes in water to make a 0.1 molar solution. This means there are 0.1 moles of NaOH dissolved in 1 liter of water. The molarity of the solution is calculated using the formula: Molarity = moles of solute / liters of solution.
What is the molarity of a solution of 95 grams of NaOH to 450 ml of water?
To calculate the molarity, you first need to convert the grams of NaOH to moles using the molar mass of NaOH (40 g/mol). Then, you divide the moles of NaOH by the volume of solution in liters (450 ml = 0.45 L) to get the molarity. Molarity = moles of NaOH / volume of solution in liters Moles of NaOH = 95 g / 40 g/mol = 2.375 mol Molarity = 2.375 mol / 0.45 L = 5.28 M
What is the molarity of a solution that contains 10.0g of NaOH in 400.0 ml of NaOH of solution?
The answer is 0,625 moles.
What is the molarity of 4mol of NaOH dissolved in 2L of water?
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, the molarity of the solution with 4 mol of NaOH dissolved in 2 L of water would be 2 M.
What is the OH- in a solution that contains 0.240 g NaOH in 0.225 L of solution?
Molarity = moles solute/Liters solution get moles NaOH 0.240 grams NaOH (1 mole NaOH/39.998 grams) = 0.0060 moles NaOH ----------------------------------as one to one OH- has this many moles also Molarity = 0.0060 moles OH-/0.225 Liters = 0.0267 M OH- ----------------------- -log(0.0267 M OH-) = 14 - 1.573 = 12.4 pH -------------
What is the molarity of 32.0 of NaOH in 450 of NaOH solution?
I assume you mean 32.0 grams of NaOH and 450 milliliters of NaOH. Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters ) get moles of NaOH 32.0 grams NaOH (1 mole NaOH/39.998 grams) = 0.800 moles NaOH Molarity = 0.800 moles NaOH/0.450 liters = 1.78 Molar NaOH
What is the molarity of a solution made by dissolving 2 moles of Na OH in 6 kg of water?
6 kg = 6000 grams and density of water = 1.00 grams/milliliters. 1.00 g/ml = 6000 grams/X ml = 6000 ml which = 6 liters ======================== Molarity = moles of solute/Liters of solution Molarity = 2 moles NaOH/6 Liters = 0.3 M NaOH solution -----------------------------
What is the molarity of 80g NaOH dissolved in 1L of water?
To find the molarity, we first need to calculate the number of moles of NaOH. The molar mass of NaOH is 40 g/mol (sodium=23g/mol, oxygen=16g/mol, hydrogen=1g/mol). Thus, 80g NaOH is 2 moles (80g / 40g/mol). Given 1L of solution, the molarity is 2 moles / 1 L = 2 M.
Dissolve 2 moles of NaOH in 6 kg of water?
To dissolve 2 moles of NaOH in 6 kg of water, you would need to calculate the molarity of the NaOH solution. First, you would find the molar mass of NaOH (40 g/mol) and then divide the moles by the mass of water in kg to find the molarity. This would be approximately 0.33 mol/L.
What is the molarity of Na OH solution?
The molarity of a NaOH solution is determined by the concentration of NaOH in moles per liter of solution. It is calculated by dividing the moles of NaOH by the volume of solution in liters. For example, a 0.1 M NaOH solution would contain 0.1 moles of NaOH per liter of solution.
How many moles of NaOH were used in the titration process?
The number of moles of NaOH used in the titration process can be calculated by dividing the volume of NaOH solution used by the molarity of the NaOH solution.
