Formaldehyde's molecular formula is CH2O, and according to the atomic masses of its constituent elements, the gas has a molar mass of 30g/mol. If you have 12.3g of it, then set up a direct proportion where 30/1=12.3/x. Solve for x to get 0.41 moles. Multiply this by the constant of 22.4 liters/mole of any gas at STP, and you get 22.4x0.41=9.184 liters CH2O at STP.
PV=nRT 32 gram O2 = 1 mole O2 (1atm)(V) = (1 mole)(.0821)(273) V = 22.4 L
At STP (standard temperature and pressure: 0 degrees Celsius and 1 atm), the volume taken up by 132 grams of propane can be calculated using the ideal gas law. First, find the number of moles of propane using its molar mass, and then use the ideal gas law equation to calculate the volume, which will be around 66.6 L.
We know that one mole of any gas at STP occupies 22.4 liters of volume. We also know that one mole of carbon dioxide is 44.01 grams of CO2. If there are 44.01 grams of this gas in 22.4 liters at STP, then there will be about 0.98 grams of CO2 in half a liter (500 ml) of the gas at STP.
At standard temperature and pressure (STP), the gas that occupies the highest volume is hydrogen.
The molar volume of hydrogen gas at STP (Standard Temperature and Pressure) is 22.4 liters per mole.
PV=nRT 32 gram O2 = 1 mole O2 (1atm)(V) = (1 mole)(.0821)(273) V = 22.4 L
The volume of any gas at STP (standard temperature and pressure) is 22.4 L/mol. The molar mass of helium is 4.0026 g/mol. So, 84.6 grams of helium would be 84.6/4.0026 = 21.1 mol. Therefore, the volume of 84.6 grams of helium at STP would be 21.1 mol * 22.4 L/mol = 472.64 L.
At standard temperature and pressure (STP), which is defined as 0 degrees Celsius and 1 atmosphere pressure, the volume of 10 grams of CO2 can be calculated using the ideal gas law. The molar mass of CO2 is 44.01 g/mol. Using the ideal gas law equation, you can determine the volume to be approximately 4.48 liters.
At STP (standard temperature and pressure: 0 degrees Celsius and 1 atm), the volume taken up by 132 grams of propane can be calculated using the ideal gas law. First, find the number of moles of propane using its molar mass, and then use the ideal gas law equation to calculate the volume, which will be around 66.6 L.
At Standard Temperature and Pressure (STP), which is defined as 0 degrees Celsius (273.15 Kelvin) and 1 atmosphere pressure, the molar volume of an ideal gas is approximately 22.4 liters/mol. The molar mass of nitrogen gas (N₂) is approximately 28.02 grams/mol. To calculate the density (D) of nitrogen gas at STP, you can use the ideal gas law: � = Molar mass Molar volume at STP D= Molar volume at STP Molar mass � = 28.02 g/mol 22.4 L/mol D= 22.4L/mol 28.02g/mol � ≈ 1.25 g/L D≈1.25g/L Therefore, the density of nitrogen gas at STP is approximately 1.25 grams per liter.
The volume of 10.9 mol of helium at STP is 50 litres.
The element is lithium (Li). It has a density of 4.54 g/cm3 and at STP (standard temperature and pressure), a volume of 1.65 cm3 would weigh approximately 7.49 grams.
We know that one mole of any gas at STP occupies 22.4 liters of volume. We also know that one mole of carbon dioxide is 44.01 grams of CO2. If there are 44.01 grams of this gas in 22.4 liters at STP, then there will be about 0.98 grams of CO2 in half a liter (500 ml) of the gas at STP.
At standard temperature and pressure (STP), the gas that occupies the highest volume is hydrogen.
At standard temperature and pressure (STP), the density of hydrogen sulfide (H₂S) is approximately 1.363 grams per liter. This value can be calculated using the molar mass of H₂S, which is about 34.08 g/mol, and the ideal gas law, considering that one mole of gas occupies 22.414 liters at STP. Therefore, the density is derived by dividing the molar mass by the volume at STP.
At STP conditions, 11g of SO2 will occupy a volume of approximately 5.6 liters.
The volume of 35.7 grams of water = 35.7 cubic centimetres at standard temperature and pressure, (STP). This means a sample at 0°C at a pressure of one atmosphere.