Because,(i) Ni(II) have d8 electronic configuration, which strongly favors square-planar complex formation;and dmg on loosing one acidic proton favors the square-planar arrangement makes the formation of [Ni(dmg)] complex favorable
(ii) Because d8 configuration is stabilized most in square-planar geometry (due to high CFSE) the formation of complex becomes more favorable which adds to the driving force of the complex formation.
The mixture of silver chloride with hydrochloric acid produces the complex ion [AgCl2] with a charge of -1. This is what will precipitate from the reaction.
Put drops of Sodium, Potassium, or Ammonium Hydroxide in it. The Cupric hydroxide will precipitate out in blue colour. Dont put excess hydroxide or there will be a formation of another intense blue complex compound
Silver chloride is a colorless aqueous solution.Added:AgCl is a quit insoluble, white precipitate, turning grayish black by reduction in visible light (photosensible reaction).AgCl will form a colourless, soluble Ag(NH3)2+ complex when dilute ammonia is added.
potassium nitrate (aq) and lead iodide (s) are formed to create a yellow cloudy substance in a yellow liquid that will settle as a powder.
When an Ammonium solution (NH4OH or simply NH3 with water) is added to Copper Sulfate (CUSO4), it forms what we call a "complex". It is called the Tetraamminecuprate(II) complex. The color of the soultion is deep blue and may form a white precipitate. Here's the reaction: Cu2+ + 4NH3 -----> Cu(NH3)4 (with a 2- charge) Only copper reacts with the ammonium, so there is no need to include the sulfate (SO4) and the hydroxide (OH-)
The purpose of the ammonium acetate in the gravimetric determination of aluminium as oxinate is as a buffer. As more ammonium acetate is added, this caused the complex of the aluminium in the solution to precipitate after the yellow supernatant was formed. Excess ammonium acetate is needed to ensure all of the crystals precipitated out completely.
precipitate can be of any color and depends upon the complex formed in precipitation.
The mixture of silver chloride with hydrochloric acid produces the complex ion [AgCl2] with a charge of -1. This is what will precipitate from the reaction.
to convert the Hb to acid-hematin which is a brown coloured complex.
Add salt to the solution. Change the temperature of the solution. Let the solvent evaporate in increase the concentration of the soluble complex. Change the pH of the solution.
I think you are referring to the test using Fehlings solution. Fehlings solution oxidises aldehydes and ketones and formic acid and is in turn reduced. The red precipitate is the copper(I) oxide formed by reduction of the copper(II) complex found in Fehlings solution. Acetic acid is not readily oxidised and so there is no precipitate. See link for more information on what the complex is in Fehlings solution and how it is prepared.
Zinc is used to precipitate gold from gold cyanide. Zinc will react to form zinc cyanide.
if the protein is colorless then it is quite tough to calculate the lambda max or absorption maxima directly (still you can check it by absorbtion maxima calculation/experiment). Otherwise, for its estimation first you have to treat it with any reagent (like folin reagent) then it will form a colored complex and then you can calculate it. For the common estimation of protein, there is a "Lowry Method" where you can calculate it on 750 wavelength.
Put drops of Sodium, Potassium, or Ammonium Hydroxide in it. The Cupric hydroxide will precipitate out in blue colour. Dont put excess hydroxide or there will be a formation of another intense blue complex compound
in DNA estimation by diphenylamine method, standard calf thymus DNA is digested by perchloric acid, but unkown is not digested by perchloric acid, rather rest protocol of diluting with water and treating with diphenylamine and checking aborbance reamins same can anybody say the reason?
In the presence of heat and acetic acid, ortho-toluidine (also called o-toluidine) reacts rapidly with aldohexoses (mostly glucose) to form a green-colored complex that can be measured at 630 nm.
Software project estimation is a form of problem solving, and in most cases, the problem to be solved (i.e. developing a cost and effort estimate for a softwa project) is too,complex to be considered in one piece. For this reason, we decompose the problem, recharacterizing it as a set of smaller(and hopefully,more manageable)problems. The decomposition approach was discussed from two different points of view: 1). decomposition of the problem and 2).decompostion of the process. Estimation uses one or both forms of partitioning.But before an estimate can be made, the project planner must understand the scope of the software to be built and generate an estimation of its"size".