The gram Atomic Mass of lithium is 6.941; this is the amount of lithium that contains Avogadro's Number of atoms. Therefore, in 18.7 g of lithium, there will be (18.7)/(6.941) times Avogadro's Number of atoms, or about 1.62 X 1024, to the justified number of significant digits.
2.32
To find the number of atoms in 11.8 g of lithium, you need to first calculate the number of moles of lithium present using the atomic mass of lithium (6.941 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
How many lithium atoms are in 10.56 g of lithium
To find the number of atoms in 187 grams of calcium, we first need to determine the number of moles of calcium. This is done by dividing the mass (in grams) by the molar mass of calcium (40.08 g/mol). Next, we can use Avogadro's number (6.022 x 10^23 atoms/mol) to calculate the number of atoms in that number of moles.
Li atomic mass= 6.941g/mol= 4.9 moles of Li1.00 mol = 6.02 x 1023 atoms4.9 mol Li = 2.95 x 1024 atoms= 3.0 x 1024 atoms
2.32
To find the number of atoms in 11.8 g of lithium, you need to first calculate the number of moles of lithium present using the atomic mass of lithium (6.941 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
How many lithium atoms are in 10.56 g of lithium
To find the number of lithium atoms, you would need to know the molar mass of lithium (6.94 g/mol) and then use the formula: Number of atoms = (0.01456 g / 6.94 g/mol) * Avogadro's number Avogadro's number is 6.022 x 10^23 atoms/mol.
54,9 g LiClO contain 16,9866.10e23 molecules.
To calculate the mass of 9.44x10^23 atoms of lithium, you can use the molar mass of lithium, which is approximately 6.94 g/mol. Divide the number of atoms by Avogadro's number to get the number of moles, then multiply by the molar mass to get the mass in grams.
To determine the number of atoms in 12.7 grams of lithium, you need to first calculate the number of moles using the molar mass of lithium (6.94 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert from moles to atoms.
Helium has 1 atom, lithium has 1 atom, beryllium has 1 atom, boron has 1 atom, carbon has 1 atom, nitrogen has 1 atom, and oxygen has 1 atom, in their natural state.
To find the number of atoms in 187 grams of calcium, we first need to determine the number of moles of calcium. This is done by dividing the mass (in grams) by the molar mass of calcium (40.08 g/mol). Next, we can use Avogadro's number (6.022 x 10^23 atoms/mol) to calculate the number of atoms in that number of moles.
To find the number of moles in 1.9 g of lithium, you need to divide the mass of lithium by its molar mass. The molar mass of lithium is approximately 6.94 g/mol. So, 1.9 g / 6.94 g/mol ≈ 0.274 moles of lithium.
Li atomic mass= 6.941g/mol= 4.9 moles of Li1.00 mol = 6.02 x 1023 atoms4.9 mol Li = 2.95 x 1024 atoms= 3.0 x 1024 atoms
Well, honey, if we're talking about lithium (Li) and you've got 55.2 grams of it, you're looking at approximately 7.4 x 10^23 atoms. That's a whole lotta Li atoms in your hands. Hope you've got a plan for all that atomic power!