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How many grams are in 1 mole of NaNO3?
The molar mass of NaNO3 is 85.0 g/mol. Therefore, 1 mole of NaNO3 is equal to 85.0 grams.
What is the mass in grams of 0.254 mol sodium nitrate?
To find the mass in grams of 0.254 mol of sodium nitrate (NaNO3), you would multiply the number of moles by the molar mass of NaNO3. The molar mass of NaNO3 is 85 grams/mol. So, 0.254 mol x 85 g/mol = 21.59 grams of sodium nitrate.
1 mol off sulfur atoms has how much mass?
The molar mass of sulfur is approximately 32.06 grams/mol. Therefore, 1 mol of sulfur atoms will have a mass of 32.06 grams.
How much mass does 1 mol of o2 gas have?
15.99 x 2 g
What is the mass in grams of 0.75 mol of sulfur which has a molar mass of approximately 32g mol?
The mass of 0.75 mol of sulfur can be calculated by multiplying the number of moles by the molar mass. Therefore, the mass would be 0.75 mol x 32 g/mol = 24 grams.
How many grams are in 1 mole of NaNO3?
The molar mass of NaNO3 is 85.0 g/mol. Therefore, 1 mole of NaNO3 is equal to 85.0 grams.
Could you convert .10 mol of NaNO3 to grams?
To convert 0.10 mol of NaNO3 to grams, you need to use the molar mass of NaNO3, which is 85 g/mol. Multiplying 0.10 mol by the molar mass will give you the answer: 0.10 mol x 85 g/mol = 8.5 grams of NaNO3.
What is the mass in grams of 0.254 mol sodium nitrate?
To find the mass in grams of 0.254 mol of sodium nitrate (NaNO3), you would multiply the number of moles by the molar mass of NaNO3. The molar mass of NaNO3 is 85 grams/mol. So, 0.254 mol x 85 g/mol = 21.59 grams of sodium nitrate.
What is the mass of NaNO3?
1 mol Na X (22.99 Na / mol Na) = 22.99 g Na1 mol N X (14.01 g N / mol N) = 14.01 g N3 mol O X (16.00 g O / mol O) = 48.00 g OMolar mass of NaNO3 = 85.00 g/mol
What is the mass of 6.0 moles of sodium nitrate (NaNO3)?
To find the mass of 6.0 moles of sodium nitrate (NaNO3), you first need to calculate the molar mass of NaNO3, which is 85.00 g/mol. Then, you multiply the molar mass by the number of moles: 85.00 g/mol x 6.0 mol = 510.0 g. Therefore, the mass of 6.0 moles of sodium nitrate is 510.0 grams.
Which weighs more 5moles of sodium nitrate or 4 moles of carbon dioxide?
I'm assuming that your instructor is using the terms mass and weight interchangeably. First determine the molar mass of each compound by multiplying the molar mass of each element by its subscript and add them together. The molar mass of an element is its atomic weight on the periodic table in grams. Molar mass of sodium nitrate (NaNO3) (1 atom Na x 22.98970g/mol Na) + (1 atom N x 14.0067g/mol N) + (3 atoms O x 15.9994g/mol O) = 84.9946g/mol NaNO3 Molar mass of carbon dioxide (CO2) (1 atom C x 12.0107g/mol C) + (2 atoms O x 15.9994g/mol O) = 44.0095g/mol CO2 Now multiply the molar mass for each compound by the number given and compare the results to determine which has the greater mass. 5mol NaNO3 x 84.9946g/mol NaNO3 = 424.973g NaNO3 4 mol CO2 x 44.0095g/mol CO2 = 176.038 So 5 moles of sodium nitrate has a mass greater than 4 moles of carbon dioxide.
What mass of silver nitrate will react with 5.85 g of sodium chloride to produce 14.35 g of silver chloride and 8.5 g of sodium nitrate if the law of conservation of mass is true?
By stoichiometry, the equation for the reaction is: AgNO3 + NaCl --> AgCl + NaNO3 From the reaction, 1 mole of AgNO3 reacts with 1 mole of NaCl to produce 1 mole of AgCl and 1 mole of NaNO3. Using the given masses, we can calculate the mass of AgNO3 needed for the reaction to occur. (Molar masses: AgNO3 = 169.87 g/mol, NaCl = 58.44 g/mol, AgCl = 143.32 g/mol, NaNO3 = 84.99 g/mol)
What is the mass of 1 mol of rubidium?
According to the periodic table, the atomic mass of rubidium, Rb is 85.5. This is numerically equal to the molar mass in g/mol. Therefore the mass of 1 mol of Rb is 85.5g.Mass of 1 mol means the molar mass of the element. Molar mass of Rubidium is 85.47 gmol-1. Rb is in the 1st group.
What is the molar mass of nitrogen dioxide?
1 mol Na X (22.99 Na / mol Na) = 22.99 g Na1 mol N X (14.01 g N / mol N) = 14.01 g N3 mol O X (16.00 g O / mol O) = 48.00 g OMolar mass of NaNO3 = 85.00 g/mol
1 mol off sulfur atoms has how much mass?
The molar mass of sulfur is approximately 32.06 grams/mol. Therefore, 1 mol of sulfur atoms will have a mass of 32.06 grams.
What is the percentage by mass of nitrogen in sodium nitrate?
The formula for sodium nitrate is NaNO3, showing that each formula unit contains one sodium atom, one nitrogen atom, and three oxygen atoms. The gram atomic masses of sodium, nitrogen, and oxygen are 22.9898, 14.0067, and 15.9994 respectively. Therefore, the percentage by mass of nitrogen in the compound is: 100{14.0067/[14.0067 + 22.9898 + 3(15.9994)]} or about 16.4795, to the justified number of significant digits.
What is the percent concentration by mass of a solution 4.2g of NaNO3 in 60 g water?
4.2 grams NaNO3/60 grams water * 100 = 7% by mass -------------------
