3
N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.
To find the number of moles of hydrogen in 3.5 moles of (NH4)2CO3, first identify the stoichiometry of the compound. In (NH4)2CO3, there are two moles of hydrogen per mole of compound. Therefore, in 3.5 moles of (NH4)2CO3, there would be 2 * 3.5 = 7 moles of hydrogen.
The balanced chemical equation for the reaction of sodium metal with water is: 2Na + 2H2O -> 2NaOH + H2 Therefore, 2 moles of sodium react with 2 moles of water to produce 1 mole of hydrogen gas. Since you have 0.068 mol of sodium, the theoretical number of moles of hydrogen gas produced would be 0.034 mol.
There are 0.5 moles of hydrogen in 1g, as the molar mass of hydrogen is 2g/mol.
The reaction of nitrogen with hydrogen to form ammonia is: N2 +3H2 = 2NH3 Therefore to make 10 moles of ammonia you need 5 moles N2 and 15 moles H2
You'll get hydrogen cyanide (HCN) plus a lot of hydrogen... C2H2 + 2NH3 = 2HCN + 3H2
The formula for tin (IV) oxide is SnO2. This formula shows that each formula unit contains exactly one tin atom. Therefore, if 0.74 mole of tin (IV) oxide is heated sufficiently to cause complete disproportionation of the compound to its constituent elements, 0.74 moles of tin metal will be produced.
First, calculate the moles of sulfuric acid used: 19.0 mL = 0.019 L. Then, use the stoichiometry of the reaction between zinc and sulfuric acid to find the moles of zinc consumed. Since one mole of zinc produces 1 mole of hydrogen gas, the moles of hydrogen gas formed will be the same as the moles of zinc consumed.
2.5 moles H2O (2 moles H/1 mole H2O) = 5 moles of hydrogen
N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.
To find the number of moles of hydrogen in 3.5 moles of (NH4)2CO3, first identify the stoichiometry of the compound. In (NH4)2CO3, there are two moles of hydrogen per mole of compound. Therefore, in 3.5 moles of (NH4)2CO3, there would be 2 * 3.5 = 7 moles of hydrogen.
Well if one mole of water = 2 moles of hydrogen and 1 mole of oxygen, than 2moles of water = 4 moles of hydrogen and 2moles of oxygen.
Methane (CH4) has four atoms of hydrogen per molecule. If there are 3 moles of methane, then there are 12 moles of hydrogen.
To find the moles of hydrogen, you can divide the given mass of hydrogen by its molar mass. The molar mass of hydrogen is approximately 1 g/mol. So, moles of hydrogen = mass of hydrogen (in grams) / molar mass of hydrogen (approximately 1 g/mol).
The balanced chemical equation for the reaction of sodium metal with water is: 2Na + 2H2O -> 2NaOH + H2 Therefore, 2 moles of sodium react with 2 moles of water to produce 1 mole of hydrogen gas. Since you have 0.068 mol of sodium, the theoretical number of moles of hydrogen gas produced would be 0.034 mol.
2 moles of benzene gives 12 moles of hydrogen atoms since benzene is C6H6
To find the number of moles of hydrogen gas, we first need to convert the mass of hydrogen gas from grams to moles using the molar mass of hydrogen gas (2 g/mol). 5.04 grams of hydrogen gas is equal to 5.04 g / 2 g/mol = 2.52 moles of hydrogen gas.