depletion region formed by either side of p&n junctions mobile charges accumulate in that places.Type your answer here...
The presence of mobile and bound charges on either sides of the pn junction causes the depletion layer. A pn junction is formed when a semiconductor is dopped with a pentavalent impurity on one side and a tri-valent impurity on the other side.on one side electrons will be more in number and on the other side holes will be more in number.At the junction the electrons combine with holes and there will be no charge carriers(i.e. electrons and holes) in that region.That region which is free from charge carriers is called depletion region.
Because the bulk charge and surface charge interacting with electric field (forward bias) creates the depletion region.
Depletion region: Consider a diode .It is a basic semiconductor.It has two regions .A cathode (Negative-N) and anode(Positiv-P) regions.The N and P when connected together forms a diode.A junction will be created at the intersection of N and p regions .N region has electrons(-ve charge) and P region has holes(+ve charge) .At the junction the electrons from N region and holes from P region will join together .Particular area at the junction will have no charged particles after that.This region is called depletion region. If we give a voltage of 0.7V ,the depletion region will decrease and there will be current flow in the device.That voltage is called thershold voltage.
The integration of the electric field across the depletion region is what develops the barrier voltage.
any capacitance is given by equation C = (epsilon * A/ d) where d is distance between two plates, thus as d reduces C increases. Now, in depletion region as we increase reverse bias, the depletion region width increases. Now consider depletion region as a parallel plate capacitor, with positive charges on n side and negative charges on p side. Thus, as reverse bias increases, d of junction capacitance increases thus capacitance reduces. On other hand, as reverse bias reduces, d of junction capacitance reduces, thus capacitance increases. -Amey Churi
depletion region formed by either side of p&n junctions mobile charges accumulate in that places.Type your answer here...
depletion region is formed only after recombination of holes and electrons..so in depletion region there are only and only immoble positive and nagative ions...hence,there is no charge carrier..
Depletion region is the region where current carriers such as electrons and holes are absent.
Depletion region forms over poles. It is due to cool weather there.
depletion region will decrease.
Because Reverse bias constrained the majority carries to repel from both side (P side & N side)hence Depletion layer is formed with a large extant of majority carriers hence the depletion region is wider in reverse bias.
in forward biasing depletion region width decreases and in reverse biasing it increases .
depletion is related to erosion and soil erosion they are pretty much formed the same way hoped this helped :)
The atmosphere does not protect the ozone depletion. It is the region where the ozone depletion occurs.
The ozone depletion is highest at the poles. Specially at the Antarctica region.
depletion layer depletion zone juntion region space charge region bipolar transistor field effect transistor variable capacitance diode
increases with doping