Emitter
in a properly biased transistor, collector and emitter current also decrease
In a forward-biased NPN transistor junction, electrons from the n-type emitter are injected into the p-type base, where they recombine with holes. This movement of charge carriers creates a flow of current from the emitter to the collector. As a result, a small input current at the base controls a larger output current flowing from the collector to the emitter, allowing the transistor to amplify signals. The overall effect is that the transistor can effectively switch or amplify electrical signals.
In the cut-off region of a transistor, the base-emitter junction is not forward-biased, meaning the transistor is effectively turned off. As a result, no current flows from collector to emitter, and the voltage across the collector to emitter (V_CE) is approximately equal to the supply voltage (V_CC) connected to the collector. Therefore, V_CE is at its maximum value, close to V_CC, indicating that the transistor is not conducting.
A: Actually it is only one transistor required for amplification the other junction can be a diode. As current Begin to flow it causes a bias across one junction which is opposite biasing for the other, A good differential amplifier will have those junction virtually at the same point with a very good current source because any mismatched will cause and output without any input. It is called voltage offset on the other end if the feedback current is very small it will also produce an output voltage offset known as current offset or basically errors
When both junctions of an NPN transistor are reverse biased, the transistor is in the cutoff mode. In this mode, the transistor is effectively turned off, and it does not conduct current between the collector and emitter. As a result, the transistor behaves like an open switch, preventing current flow in the circuit.
collector
in a properly biased transistor, collector and emitter current also decrease
Collector-to-Emitter resistance is high when the transistor is biased off.
For a transistor to be in active region : Base Emitter junction should be forward biased and Emitter collector junction should be reverse biased.
a transistor in active region when emitter junction is forward biased nd collector junction is reverse biased
To know if a transistor is PNP or an NPN,the following should be verified:For a PNP transistor, the base-collector junction is forward biased while the base-emitter junction is reversed biased.For an NPN transistor, the base-emitter junction is forward biased while the base -collector junction is reversed biased.
In a forward-biased NPN transistor junction, electrons from the n-type emitter are injected into the p-type base, where they recombine with holes. This movement of charge carriers creates a flow of current from the emitter to the collector. As a result, a small input current at the base controls a larger output current flowing from the collector to the emitter, allowing the transistor to amplify signals. The overall effect is that the transistor can effectively switch or amplify electrical signals.
Yes1
A transistor works as am amplifier by virtue of the fact that you can control the current in one path with a smaller current in another path. In a typical class A (common emitter) configuration, a certain current from base to emitter will create a corresponding current from collector to emitter. Increasing or decreasing the base-emitter current will cause a corresponding increase or decrease in the collector-emitter current, by a ratio that is defined as hFe, or beta-gain. Of course, this means that you have to properly bias the transistor, and understand the nature of hFe. You can operate a transistor in cutoff mode or saturated mode if you exceed the hFe limits. Within the limits, a properly biased transistor exhibits a (generally) linear operation.
Common base transistor if the emitter is open current Ie=0 but a small collector current thus exist.this current is reversed biased collector to the base voltage it is represented by Icbo while common emitter is d base terminal is open circuit and the base junction is reversed biased current Icbo flow from the tcollector to the emitter in the external circuit this current is called leakage current.
In the context of a bipolar junction transistor (BJT), the saturation region refers to the state where both the base-emitter and base-collector junctions are forward-biased, allowing maximum current to flow from collector to emitter. The active region occurs when the base-emitter junction is forward-biased while the base-collector junction is reverse-biased, enabling the transistor to amplify signals. The cutoff region is when both junctions are reverse-biased, resulting in minimal current flow, effectively turning the transistor off. These regions define the operational modes of the transistor in electronic circuits.
The question is poorly phrased and needs a grammatical cleanup. If you mean to ask "what happens to the collector-emitter current of a transistor when the emitter-base junction is reverse biased" then the answer is that the transistor will turn off, and you will only see leakage current.