unless you are refferring to a mole as in the animal, there is no answer to that question. Mole is just a number for a conversion factor of amu to grams.
A mole is ~6.022 x 10E23 of anything. Just as a dozen is 12 of anything.
The average oxygen atom is 16 amu and the average Ca atom is about 40 amu. So one molecule of CaO would be 56 amu. 1 mole of CaO would be 56 grams. So I guess you could say there is less than one mole in 35 grams of CaO.
Coincidently I don't think you could hide an average mole (the animal) in 35 grams of CaO either.
25.0g of KNO3
1. Locate K, N, O in your Periodic Table and get the Atomic Mass of each (for Oxygen you mulitply by 3 because of the subscript) add them all togher.
2. Take the sum of the atomic numbers for KNO3 and set up the equation as
(25.0g)(1 Mole/101.102g) = your ans.
The formula weight of calcium nitrate is approximately 102 g/mol.
25.50g / 102g/mol = 0.25 moles.
Formula mass of calcium sulfate, CaSO4 = 136.1
Amount of CaSO4 = 25.35 / 136.1 = 0.186mol
Calculate the moles in CaCl2 in a 25.00 g sample
0.1862 moles
How many moles in 311mg CaCo3
25 g CaCl2 is equivalent to 0,225 moles.
25 grams of steam are in 25 grams of water.
For this you need the atomic (molecular) mass of NaHCO3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaHCO3=84.0 grams110 grams NaHCO3 / (84.0 grams) = 1.31 moles NaHCO3
694 mL of glucose solution 0,2 M are needed.
The answer is 25 dekameter
Wendy has traveled 6/10 of the 50 states.How many is this
If I take a radioactive sample of 400 moles of an unknown substance and let it decay to the point of three half-lives I would have 50 moles left of the sample. 1/2 of what is left will decay in the next half-life. At the end of that half-life I will have 25 moles left of the unknown substance or 4/25.
.071 moles
there is .42 moles
Sr is 87.6g/mol, and 25/87.6 = 0.285 moles.
2.0^25 moles of silver nitrate is .0301 moles.
25 miles = 40.2336 kilometres
25 moles of sulfur dioxidecontain 800,825 g oxygen.
The answer is 64,9 moles.
3.00 M, or 3 moles per (L) "liter" calls for having 3 moles per liter of the solution. The question asks how many moles must be in 250ml of a solution that has 3 moles per Liter. You must ask yourself what percent of 1 Liter is 250mls? Since there are a thousand ml in one liter, (1000ml=1L), then 250ml is exactly 25% of a Liter, or .25L. So, 250ml can only hold 25% of the 3.00 Molarity. Meaning that you multiply 3 x .25 and get .75 moles.
.003 mols .003 mols
800 g oxygen are needed.
You'll need: 0.450 (L) * 25 (mol/L) = 11.25 mol CaCl2 and add water to it up to 450 mL.To be weighted:11.25 (mol CaCl2) * [40.08 + 2*35.45](g/mol CaCl2) = 1491.736 g = 1500 g =1.5 kg CaCl2 (CaCl2 as dry substance!, not hydrated)