The total momentum of the bullet and the gun before firing is zero, as the gun and the bullet are at rest. Momentum is the product of mass and velocity, and since both the gun and the bullet are not moving, their momentum is zero.
Exactly the same as whatever it was before firing. If the loaded gun was not movingbefore the trigger was pulled, then the total momentum of the gun and bullet afterfiring add up to zero.
Using the principle of conservation of momentum, we can calculate that the gun will recoil at 0.08 m/s in the opposite direction of the bullet. The total momentum of the gun and bullet before firing is equal to the total momentum after firing.
Because linear momentum is conserved. Before the shot, the momentum of (gun + bullet) is zero, so it has to be zero after the shot. The bullet gains forward momentum when fired, so the gun must gain reverse momentum in order to maintain the zero sum.
By conservation of momentum, the momentum of the gun and bullet system before firing must equal the total momentum after firing. Therefore, the velocity at which the gun recoils can be calculated by using the equation: (mass of bullet * velocity of bullet)/mass of gun = velocity of gun. Substituting the values given: (0.06 kg * 500 m/s) / 5 kg = 6 m/s.
If the gun is stationary before the shot, then the momentum of the gun and the momentum of the bullet are equal and opposite after the shot.
Using the principle of conservation of momentum, the momentum of the bullet before the gunshot is equal to the momentum of the bullet and gun after the shot. Calculating the recoil velocity using this principle shows that the gun will recoil at 1.6 m/s in the opposite direction.
the conversion of momentum law states that the total momentum of twos systems must be equal therefore M1V1 = M2V2 i am assuming the mass of the bullet is 0.0050 kg and not 50kg so (0.0050 * 250) = ( 9 * X) X = (1.25 / 9) X = 0.139 You can't answer these kind of questions with so few parameters. The bullet diameter, barrel length, powder burn rate all greatly effect the answer. The recoil is caused mainly by the gas exiting the barrel, hence muzzle brakes work.
This is conservation of momentum. You have the hot gases from the explosive charge along with the bullet moving out the barrel, away from the person. Momentum is mass times velocity. While the mass of the bullet and gases are small, the velocity is very high. So nothing was moving before the trigger was pulled, so net momentum is zero. After the trigger is pulled, the momentum is still net zero. Any momentum away from the gunner will have an equal momentum (the gun recoiling) toward him. Since the gun has much more mass than the bullet, the velocity is much less.
By Newton's third law of motion, for every action, there is an equal and opposite reaction. When a gun fires a bullet, the bullet gains momentum in one direction, causing the gun to recoil in the opposite direction with an equal amount of momentum. So the momentum of the bullet is equal in magnitude to the momentum of the gun, but in opposite directions.
A bullet fired from a gun has more momentum than a train at rest because momentum is the product of an object's mass and velocity. The bullet, despite being smaller in mass compared to the train, can have a significantly higher velocity, resulting in a greater momentum.
The momentum of the bullet is equal in magnitude but opposite in direction to the momentum of the gun. Use conservation of momentum to find the speed of the gun recoil. Since momentum is conserved, the momentum of the gun and bullet before they are fired is equal to the combined momentum of both after they are fired.