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How many moles of carbon are in 3.5 moles of calcium carbonate?
The number of moles of calcium carbonate are 3.5 moles. , there are 1 mole of calcium (Ca) atom, 1 mole of carbon (C) atom and 3 moles of oxygen (O) atoms.
How much volume of carbon dioxide is required to be bubbled through lime water to precipitate 20 gram of calcium carbonate?
To determine the volume of carbon dioxide needed, you would need to know the stoichiometry of the reaction between carbon dioxide and calcium carbonate. In this case, since 20 grams of calcium carbonate is given, you would convert that to moles using the molar mass of calcium carbonate. Then, using the balanced equation, you can determine the mole ratio between carbon dioxide and calcium carbonate. Finally, using the molar volume of carbon dioxide gas at the given conditions (usually 22.4 L/mol at standard temperature and pressure), you can calculate the volume of carbon dioxide needed.
What Mass Of Calcium Carbonate Is Needed For Complete Reaction With The HCl In 2HCl(aq) plus CaCO 3 (s) CaCl 2 (aq) plus H 2 O(l) plus CO 2 (g)?
To determine the mass of calcium carbonate (CaCO₃) needed to react completely with hydrochloric acid (HCl), you can use stoichiometry. The balanced equation shows that 2 moles of HCl react with 1 mole of CaCO₃. Thus, for every 2 moles of HCl, you need 1 mole of CaCO₃. If you know the amount of HCl in moles, you can calculate the required moles of CaCO₃ and then convert that to mass using its molar mass (100.09 g/mol).
How many grams is contained in 0.27 moles of calcium?
0,27 moles of calcium contain 10,82 g calcium.
What is 1.72 moles of magnesium carbonate in formula units?
To convert moles of magnesium carbonate (MgCO₃) to formula units, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) formula units per mole. Therefore, 1.72 moles of magnesium carbonate is calculated as follows: [ 1.72 , \text{moles} \times 6.022 \times 10^{23} , \text{formula units/mole} \approx 1.034 \times 10^{24} , \text{formula units}. ] Thus, 1.72 moles of magnesium carbonate is approximately (1.034 \times 10^{24}) formula units.
How many grams are in 2.8 moles of calcium carbonate?
2,8 moles of calcium carbonate have 240,208 g.
How many moles of carbon are in 3.5 moles of calcium carbonate?
3.5 moles CaCO3 (1 mole carbon/1 mole CaCO3) = 3.5 moles
How do you convert 50 g of calcium carbonate into moles?
1. Calculate formula massCalcium carbonate has chemical formula CaCO3.Its formula mass is 40.1 + 12.0 + 3(16.0) = 100.12. Apply formula to calculate number of moles of CaCO3Amount of CaCO3= mass/formula mass= 50/100.1= 0.50mol
How many moles of carbon are in 3.5 moles of calcium carbonate?
The number of moles of calcium carbonate are 3.5 moles. , there are 1 mole of calcium (Ca) atom, 1 mole of carbon (C) atom and 3 moles of oxygen (O) atoms.
How many moles of calcium atoms are 2.5 moles of calcium carbonate CaCO3?
The formula given shows that each formula unit or mole contains one calcium atom; therefore, 2.5 moles of calcium chloride contains 2.5 moles of calcium atoms.
How many moles of stomach acid would be neutralized by one tablet of regular strength maalox that contains 600 mg of calcium carbonate?
To calculate the number of moles of stomach acid neutralized by calcium carbonate, you first need to convert the mass of calcium carbonate (600 mg) to grams (0.6 g). Then, use the molar mass of calcium carbonate (100.09 g/mol) to find the number of moles. Finally, use the balanced chemical equation to determine the moles of stomach acid neutralized.
What mass of calcium oxide is produced by heating 25 moles of calcium carbonate?
The molar ratio between calcium carbonate and calcium oxide is 1:1. So, 25 moles of calcium carbonate will produce 25 moles of calcium oxide. The molar mass of calcium oxide is 56.08 g/mol, so the mass of calcium oxide produced will be 25 moles * 56.08 g/mol = 1402 g.
How may grams of calcium carbonate will be needed to form 4.29 liters of carbon dioxide?
To calculate the grams of calcium carbonate needed, you first need to determine the moles of carbon dioxide produced (using the ideal gas law). Then, since 1 mole of CO2 is produced for every mole of CaCO3 consumed, you can convert moles of CO2 to moles of CaCO3. Finally, use the molar mass of CaCO3 to convert moles to grams.
How many moles of calcium carbonate are in one roll tums that contain 12 tablets?
Assuming each Tums tablet contains 500 mg of calcium carbonate, there is a total of 6 grams of calcium carbonate in one roll of Tums (12 tablets x 500 mg). To calculate the number of moles, divide the mass by the molar mass of calcium carbonate (100.09 g/mol), yielding around 0.06 moles of calcium carbonate in one roll of Tums.
How many grams of calcium chloride will be produced when 30.0 g of calcium carbonate are combined with 12.0 g of hydrochloric acid?
To find the amount of calcium chloride produced, first calculate the moles of calcium carbonate and hydrochloric acid using their molar masses. Then, determine the limiting reactant and use stoichiometry to find the moles of calcium chloride produced. Finally, convert moles of calcium chloride to grams using its molar mass.
How many moles of calcium carbonate are in 1.719 grams?
Calcium carbonate, CaCO3 has formula mass of 40.1+12.0+3(16.0) = 100.1Amount of CaCO3 = 1.719/100.1 = 0.0172molThere are 0.0172 moles of calcium carbonate in a 1.719 gram pure sample.
What is the mass of 0.5 moles of calcium carbonate?
The molar mass of calcium carbonate (CaCO3) is 100.09 g/mol. Therefore, the mass of 0.5 moles of calcium carbonate would be 0.5 mol x 100.09 g/mol = 50.045 grams.
