There are always the same number of MOLECULES in a mol.
That number is avogadro's number, "6.022×10^23". It's a huge number.
Now if instead of molecules we have single atoms, then you have 6.022×10^23 atoms in a mol. A mol is like saying "You have 6.022×10^23 parts of that." Regardless of what "that" is. I could have a mol of apples but it would be more apples than anyone has ever seen.
So the answer is 1 mol of Nitrogen is 6.022×10^23 atoms.
HOWEVER. Nitrogen as a species tends to be diatomic, so it's a little bit of a trick question. In most circumstances each molecule has 2 atoms (N2) so your answer is double. You have 6.022×10^23 molecules, but 12.044×10^23 atoms. Really the question isn't quite specific enough and you'll have to make a judgement on whether they mean elemental nitrogen or nitrogen as we commonly find it existing in nature.
200. The formula is for every 1 Oxygen atom, 2 Hydrogen atoms must be present in water. Otherwise you would produce H2O2 (you cannot make it HO because it is never found in molecules on it's own) which is bleach.
100/150.158 is 0.666 moles
100 times Avogadro's Number = 6.022 X 1025.
For this problem you need the atomic masses of the elements to find the molecular mass (added atomic masses). Then take the atomic mass of Cl and divide it by the molecular mass (multiplied by 100) to get a percent. This will be the percent of Cl in all compounds of HCl. Then you can use this percent and apply it to the 2 moles.H- 1.00Cl- 35.5HCl- 36.535.5 / 36.5 × 100 = 97.3% Cl in HClSo we know that in 2 moles of HCl, 97.3% of it is Cl.97.3% of 2.00 moles HCl = 1.95 moles of Cl in 2 moles HClNow we have to find out how many atoms this is (convert moles to atoms). Take the number of moles and multiply it by Avogadro's constant, 6.02 × 1023.1.95 moles Cl × 6.02 × 1023 = 1.17 × 1024atoms of Cl in 2 moles of HCl
To find the mass of argon in grams for 100 moles, you can use the molar mass of argon, which is approximately 40 grams per mole. Therefore, the mass of 100 moles of argon would be calculated as follows: 100 moles × 40 g/mole = 4000 grams. Thus, there are 4000 grams of argon in 100 moles.
To find the number of moles of phosphorus atoms in 100 grams of P4S10, we first need to determine the molar mass of P4S10 which is 284.26 g/mol. Next, we calculate the number of moles of P4S10 in 100 grams by dividing 100 g by the molar mass to get 0.352 moles of P4S10. Since there are 4 phosphorus atoms in each P4S10 molecule, there are 0.352 moles x 4 = 1.41 moles of phosphorus atoms in 100 grams of P4S10.
Two atoms of nitrogen form the gaseous, natural state, of nitrogen. 10.62 grams N2 (1 mole N2/28.02 grams)(6.022 X 10^23/1 mole N2)(1 mole N2 atoms/6.022 X 10^23) 0.3790 mole of gaseous nitrogen atoms ------------------------------------------------------ * as you may see, Avogadro's number is over itself as a form of one and is a superfluous step put there for formality's sake
The gram atomic mass of phosphorus is 30.9738, and by definition, a mole of such atoms contains Avogadro's Number of atoms. Therefore, 100 g of phosphorus contains 100/30.9738 or 3.23 moles, to the justified number of significant digits.
The molar mass of sulfur is approximately 32 grams per mole. Therefore, 100 grams of sulfur would contain approximately 3 moles of sulfur atoms (100 grams / 32 grams/mole). To find the number of atoms, you would then multiply the number of moles by Avogadro's number (6.022 x 10^23 atoms/mole) to get the total number of sulfur atoms in 100 grams.
200. The formula is for every 1 Oxygen atom, 2 Hydrogen atoms must be present in water. Otherwise you would produce H2O2 (you cannot make it HO because it is never found in molecules on it's own) which is bleach.
To find the number of atoms in 100 grams of gold, you would first calculate the number of moles using the molar mass of gold (197 grams/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. So, approximately 3.01 x 10^23 atoms of gold are present in 100 grams.
The atomic weight of magnesium is 24.31; therefore, the number of moles in 100 gm is 100/24.31 = 4.11, to the justified number of significant digits.
100/150.158 is 0.666 moles
Ammonium sulfide has the formula (NH4)2S, which contains 2 nitrogen atoms. One mole of (NH4)2S contains 2 moles of nitrogen. In 8.941 mol of (NH4)2S, there are 8.941 x 2 = 17.882 mol of nitrogen. To find the percent of nitrogen by weight, you would compare the molar mass of nitrogen to the molar mass of the compound and then multiply by 100.
100 times Avogadro's Number = 6.022 X 1025.
Aluminum sulfide has a molar mass of 150.16 grams per mole. This means there are 0.666 moles present, or 4.01 E23 molecules. Each molecule of Al2S3 has 2 aluminum atoms, so there are 8.02 E23 atoms of aluminum present.
95,474 moles