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the question is directing a discussion of Avagadro's number.

If Nitrogen were an ideal gas ( it isn't) there would be 6,02 X 10 ^23 atoms

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What is the mass of nitrogen in grams?

One mole of atoms of an element is equal to the atomic mass of that element expressed in grams. Nitrogen-14 so one mole of nitrogen weighs 14 g


How do you calculate the number of atoms in 6980 of nitrogen?

To calculate the number of atoms in 6980 grams of nitrogen, you would first convert the mass of nitrogen to moles using the molar mass of nitrogen (~14 g/mol). Then, you would use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. Overall, the calculation would be 6980 grams of nitrogen * (1 mol / 14 grams) * (6.022 x 10^23 atoms / 1 mol).


How do you convert 2.2 grams in to atoms in nitrogen?

To convert grams to atoms, you need to first convert grams of nitrogen to moles using its molar mass (14.01 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. So, for 2.2 grams of nitrogen: Convert grams to moles: 2.2 g / 14.01 g/mol = 0.157 moles. Convert moles to atoms: 0.157 moles x 6.022 x 10^23 atoms/mol = 9.46 x 10^22 atoms of nitrogen.


How many moles of nitrogen are there in 29 grams of nitrogen?

There are 29/14, or just over 2 moles of nitrogen in 19 grams.


How many moles of nitrogen in 42 grams of nitrogen?

As a rule of thumb, the atomic mass of an element equals the number of grams of that element equals a mole. Since the atomic mass of Nitrogen is 14, there are 14 grams in one mole of Nitrogen. Next, we just have to divide 42 by 14 and we get our answer: There are 2.9988 moles in 42 grams of Nitrogen.


How much more massive is 14 grams of nitrogen than an 3 grams of nitrogen?

It is 14 - 3 = 11 grams more massive.


What are the nitrogen atoms?

Nitrogen atoms, of course. Naturally occurring nitrogen has two isotopes: nitrogen-14 and nitrogen-15.


What mass of hydrogen contains the same number of atoms as 7.00g of nitrogen?

Let's see. 7.00 grams nitrogen (1 mole N/14.01 grams)(6.022 X 10^23/1 mole N) = 3.01 X 10^23 atoms of nitrogen 3.01 X 10^23 ( 1mole H/6.022 X 10^23)(1.008 grams/1 mole H) = 0.504 grams of hydrogen


What is the mass of 5.49E25 nitrogen atoms?

6.02 x 1023 atoms of nitrogen will weigh 14 g.So, 5.49 x 1025 atoms of nitrogen will weigh 1277 g.


How many nitrogen-14 atoms would you need to place on the right pan to balance the three calcium-42 atoms on the left pan of the atomicbalance?

You would need to use 14 nitrogen-14 atoms on the right pan to balance the three calcium-42 atoms on the left pan. This is because nitrogen-14 has an atomic mass of 14, while calcium-42 has an atomic mass of 42. By multiplying the atomic mass of nitrogen-14 by 3, you would obtain a total mass of 42, thus balancing the equation.


What mass of nitrogen is needed to make 34 grams of ammonia?

To find the mass of nitrogen needed to make ammonia, first determine the molar mass of ammonia (NH3) which is 17 g/mol. Since there is one nitrogen atom in ammonia, the nitrogen mass is 14 g/mol. To make 34 grams of ammonia, you would need 14 grams of nitrogen.


When 40 grams of ammonium nitrate explode 14 grams of nitrogen qnd 8 grams of oxygen form How many grams of water form?

if 14 grams of nitrogen is formed, then 8 grams of oxygen, add those two together and you get 22. and that's 22 of the 40 grams used, so 40 subtracted by 22 is 18. 18 grams of water would be formed.