6.022*10^23
Number of nitrogen atoms in 1 mole nitrogen dioxide? Nitrogen dioxide has 1 N atom and 2 O atoms. One mole of nitrogen dioxide has 1 mole of N atoms
Since the atomic weight of oxygen is 15.9994 or 15.9994 grams/mole 16.00 grams of O would be 1.000 moles. 1 mole of something contains Avogadro's number (6.0221415 × 1023 mol-1) of particles of that substance - in this case atoms so 16.00 grams of O would be 6.0221415 × 1023 atoms of O.
You must mean; how many grams of O ( one atom oxygen ) 1.23 X 10^24 molecules H2O (1 mole H2O/6.022 X 10^23)(1 mole O/1 mole H2O)(16 grams/1 mole O) = 32.7 grams of oxygen
1 mole of O atoms, or 0.5 moles of o2 molecules.
The Avogadro number: 6,02214129(27)×1023.
1 mole H2SO4 x 4 moles O/mole H2SO4 x 6.02x10^23 atoms of O/mole O = 2.4x10^34 oxygen atoms
1 mole of Li₂O contains 2 moles of lithium (Li) atoms and 1 mole of oxygen (O) atoms. Therefore, in 1 mole of Li₂O, there are a total of 3 moles of atoms.
0.87 grams water (1 mole H2O/18.016 grams)(1 mole O/1 mole H2O)(6.022 X 1023/1 mole O) = 2.9 X 1022 atoms of oxygen --------------------------------------
There are 6.022x10^23 atoms in one mole of oxygen, or Avogadro's number.
6.02214076×1023
The formula with this disaccharide is, C12H22O11 17.1 grams C12H22O11 (1 mole C12H22O11/342.296 grams)(11 mole O/1 mole C12H22O11)(6.022 X 10^23/1 mole O) = 3.31 X 10^23 atoms of oxygen ------------------------------------------
In 52.06g of carbon dioxide (CO2), you have 1 mole of CO2, which contains 2 moles of oxygen atoms. Each mole of oxygen atoms is equivalent to 6.022 x 10^23 atoms. Therefore, in 52.06g of CO2, there are 2 x 6.022 x 10^23 oxygen atoms.
C6H6O2 This is hydroquinone, one of several types, but I will use this one as example. 0.20 moles C6H6O2 (2 mole O/1 mole C6H6O2)(6.022 X 1023/1 mole O) = 2.4 X 1023 atoms of oxygen =====================
1 mole N2O3 (3 moles O/1 mole N2O3) = 3 moles oxygen atoms ==================
6.02x10^23
1 mole CaCO3 (3 mole O/1 mole CaCO3) = 3 moles oxygen
1 mole O = 15.9994g = 6.022 x 1023 atoms 1810 atoms O x 15.9994g/6.022 x 1023 atoms = 4.81 x 10-20g