One mole is 6.02 × 1023 of anything. One mole of atoms is 6.02 × 1023 atoms, one mole of rice is 6.02 × 1023 grains, one mole of shoes is 6.02 × 1023 shoes.
So you take 1.1 and multiply it with 6.02 × 1023 to get 6.62 × 1023
To find the number of moles of CO molecules, divide the given number of molecules by Avogadro's number. Avogadro's number is about 6.022 x 10^23 molecules/mol. Therefore, 7.20 x 10^27 molecules of CO corresponds to 12 moles (7.20 x 10^27 / 6.022 x 10^23).
There are 6.023x10^23 molecules in one mole of a compound. So now, you have to find how many moles of each compound you have. CO's molecular weight is (12+16) = 28 g/mol N2's molecular weight is (14+14) = 28 g/mol So you find the moles of each. moles of N2 = 20g/ 28g/mol = .714 moles moles of CO = 16g / 28 g/mol = .571 moles So, N2 has (.714 *6.023x10^23) has 4.3 x10^23 molecules and CO (.571 *6.023x10^23) has 3.4x10^23 molecules. So, 20g of N2 has more molecules than 16g of CO
To find the number of molecules in 2.10 moles of CO₂, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) molecules per mole. Multiplying the number of moles by Avogadro's number gives: [ 2.10 , \text{mol} \times 6.022 \times 10^{23} , \text{molecules/mol} \approx 1.26 \times 10^{24} , \text{molecules} ] Therefore, there are approximately (1.26 \times 10^{24}) molecules in 2.10 moles of CO₂.
If you have 0.5 moles of K₂CO₃, then you simply have 0.5 moles of K₂CO₃. The quantity of moles is a direct measurement, so there are no additional calculations needed. Therefore, the answer is 0.5 moles of K₂CO₃.
The answer is 10 moles of carbon monoxide.2 C + O2 = 2 CO
To find the number of moles of CO molecules in 52g of CO, we first need to determine the molar mass of CO, which is approximately 28 g/mol. Then, we divide the given mass by the molar mass to get the number of moles. So, 52g of CO is equivalent to approximately 1.86 moles of CO molecules.
To find the number of moles of CO molecules, divide the given number of molecules by Avogadro's number. Avogadro's number is about 6.022 x 10^23 molecules/mol. Therefore, 7.20 x 10^27 molecules of CO corresponds to 12 moles (7.20 x 10^27 / 6.022 x 10^23).
1 mole contains 6.022 x 1023 molecules. number of moles of CO= (4.65 x 1024) / (6.022 x 1023) = 7.72 mol The identity of the molecule does not change the answer.
To find the number of molecules in 140g of CO (carbon monoxide), first calculate the number of moles using the molar mass of CO (28.01 g/mol). Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. In this case, 140g of CO corresponds to about 5 moles, which is approximately 3.01 x 10^24 molecules.
To find the number of molecules in 140 g of CO (carbon monoxide), you first need to determine the number of moles of CO. The molar mass of CO is 28 g/mol. Divide the given mass by the molar mass to get the number of moles, then use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
There are 6.023x10^23 molecules in one mole of a compound. So now, you have to find how many moles of each compound you have. CO's molecular weight is (12+16) = 28 g/mol N2's molecular weight is (14+14) = 28 g/mol So you find the moles of each. moles of N2 = 20g/ 28g/mol = .714 moles moles of CO = 16g / 28 g/mol = .571 moles So, N2 has (.714 *6.023x10^23) has 4.3 x10^23 molecules and CO (.571 *6.023x10^23) has 3.4x10^23 molecules. So, 20g of N2 has more molecules than 16g of CO
4,54 L of CO have 0,182 moles.
To find the number of molecules in 2.10 moles of CO₂, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) molecules per mole. Multiplying the number of moles by Avogadro's number gives: [ 2.10 , \text{mol} \times 6.022 \times 10^{23} , \text{molecules/mol} \approx 1.26 \times 10^{24} , \text{molecules} ] Therefore, there are approximately (1.26 \times 10^{24}) molecules in 2.10 moles of CO₂.
If you have 0.5 moles of K₂CO₃, then you simply have 0.5 moles of K₂CO₃. The quantity of moles is a direct measurement, so there are no additional calculations needed. Therefore, the answer is 0.5 moles of K₂CO₃.
The answer is 10 moles of carbon monoxide.2 C + O2 = 2 CO
To find the number of molecules of carbon monoxide in 3.69 grams, first calculate the number of moles using the molar mass of carbon monoxide (28.01 g/mol). Next, use Avogadro's number to determine the number of molecules in those moles of carbon monoxide.
382 g Co contain 6,482 moles.