4,5.10e28 molecules of sodium fluoride NaF are equal to 0,745.10e5 moles.
Theoretically the mass is 62,3018 g.
1.60 x 10^24 molecules
6.355 x 10e10 atoms of iron contain 58,93.e-13 grams
To obtain one mole of iron atoms, you need to weigh out approximately 55.85 grams of iron. This is because the molar mass of iron (Fe) is about 55.85 grams per mole. Therefore, for one mole, you simply measure out this amount in grams.
4.5 moles
Multiply the number of moles by the molecular weight.
4,5.10e28 molecules of sodium fluoride NaF are equal to 0,745.10e5 moles.
To calculate the number of grams of iron, you need to convert the number of iron atoms (6.02 x 10^23) into moles by dividing by Avogadro's number (6.022 x 10^23 atoms/mol). Then, multiply the number of moles of iron by the molar mass of iron (55.85 g/mol) to find the grams of iron. This would result in approximately 55.85 grams of iron.
1 mg of iron is equal to 0.001 grams of iron.
To find the mass of fluorine produced, first calculate the mass of sodium fluoride: 27.7 grams of sodium / (1 part sodium / 1 part sodium fluoride) = 27.7 grams of sodium fluoride Now, since the ratio of sodium to fluorine in sodium fluoride is 1:2 (1 part sodium to 2 parts fluorine), the mass of fluorine is 27.7 grams / 2 = 13.85 grams.
Theoretically the mass is 62,3018 g.
There are 0.35 grams of iron in 350 mg. To convert milligrams (mg) to grams (g), you can divide by 1000.
738 grams iron are equivalent to:- 12,626 moles- 76.10e23 atoms
To find the number of grams in 4.5 moles of sodium fluoride, you would multiply the number of moles by the molar mass of sodium fluoride. The molar mass of sodium fluoride (NaF) is approximately 41 g/mol. So, 4.5 moles x 41 g/mol = 184.5 grams of sodium fluoride.
25 grams / (17 grams/mole) x 6.022x1023 molecules/mole = 8.9x1023 molecules
To find the grams of sodium fluoride needed, use the formula: grams = moles x molar mass. First calculate the moles by multiplying the volume (6.3 L) by the molarity (3.6 mol/L). Then multiply the moles by the molar mass of sodium fluoride (41.99 g/mol) to find the grams required. In this case, approximately 920 grams of sodium fluoride are needed.