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How many molecules are in 1.65 grams of sodium fluoride?

4.5 moles


How can you convert from molecules to grams?

Multiply the number of moles by the molecular weight.


How many moles are in 4.5X1028 molecules of sodium fluoride NaF?

4,5.10e28 molecules of sodium fluoride NaF are equal to 0,745.10e5 moles.


How many grams of iron are in 6.02 X 1023 atoms of iron?

To calculate the number of grams of iron, you need to convert the number of iron atoms (6.02 x 10^23) into moles by dividing by Avogadro's number (6.022 x 10^23 atoms/mol). Then, multiply the number of moles of iron by the molar mass of iron (55.85 g/mol) to find the grams of iron. This would result in approximately 55.85 grams of iron.


How many grams of iron are in Mg of iron?

1 mg of iron is equal to 0.001 grams of iron.


How much fluorine in grams was formed when the mass ratio of sodium to fluorine in sodium fluoride is 1 to 21 to 1 A sample of sodium fluoride produced 27point7 grams of sodium upon decomposition?

To find the mass of fluorine produced, first calculate the mass of sodium fluoride: 27.7 grams of sodium / (1 part sodium / 1 part sodium fluoride) = 27.7 grams of sodium fluoride Now, since the ratio of sodium to fluorine in sodium fluoride is 1:2 (1 part sodium to 2 parts fluorine), the mass of fluorine is 27.7 grams / 2 = 13.85 grams.


How many grams of magnesium fluoride would you produce if you added 24 grams of magnesium to 38 grams of fluorine?

Theoretically the mass is 62,3018 g.


How many grams of iron are in 350 Mg of iron?

There are 0.35 grams of iron in 350 mg. To convert milligrams (mg) to grams (g), you can divide by 1000.


How many moles on 738 grams or iron and how many atoms?

738 grams iron are equivalent to:- 12,626 moles- 76.10e23 atoms


How many grams are in 4.5 moles of sodium fluoride?

To find the number of grams in 4.5 moles of sodium fluoride, you would multiply the number of moles by the molar mass of sodium fluoride. The molar mass of sodium fluoride (NaF) is approximately 41 g/mol. So, 4.5 moles x 41 g/mol = 184.5 grams of sodium fluoride.


How many molecule in 25 grams of NH3?

25 grams / (17 grams/mole) x 6.022x1023 molecules/mole = 8.9x1023 molecules


How many grams of sodium fluoride are needed to make 6.3 liters of a 3.6 molar solution?

To find the grams of sodium fluoride needed, use the formula: grams = moles x molar mass. First calculate the moles by multiplying the volume (6.3 L) by the molarity (3.6 mol/L). Then multiply the moles by the molar mass of sodium fluoride (41.99 g/mol) to find the grams required. In this case, approximately 920 grams of sodium fluoride are needed.